Rewrite the equations of the given boundary lines:
<em>y</em> = -<em>x</em> + 1 ==> <em>x</em> + <em>y</em> = 1
<em>y</em> = -<em>x</em> + 4 ==> <em>x</em> + <em>y</em> = 4
<em>y</em> = 2<em>x</em> + 2 ==> -2<em>x</em> + <em>y</em> = 2
<em>y</em> = 2<em>x</em> + 5 ==> -2<em>x</em> + <em>y</em> = 5
This tells us the parallelogram in the <em>x</em>-<em>y</em> plane corresponds to the rectangle in the <em>u</em>-<em>v</em> plane with 1 ≤ <em>u</em> ≤ 4 and 2 ≤ <em>v</em> ≤ 5.
Compute the Jacobian determinant for this change of coordinates:

Rewrite the integrand:

The integral is then

Answer:
a)50%,b)70%
Step-by-step explanation:
odd=5
10=100%
5
5×100=500/10
=50%
10=100%
(7×100)/10=70
The slope is 8.5, the y-intercept is 6, y=mx+b was the original formula and m=slope and b=y-intercept :)
The total cost is 455.26.
First, you do the math of the students and the chaperones. Students were $387 and the chaperones was $50.75.
Then, add. You get $437.75.
Now, add that 4% fee. That was $17.51
In all, it's $455.26.