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vesna_86 [32]
3 years ago
14

The sum of the present ages of lily and Chris is 36. In 4 years time, the sum of their ages will equal twice Lily’s present age?

How old are they now?
Mathematics
1 answer:
Andrews [41]3 years ago
7 0

Answer:

If the present age is x, then age n years later/hence = x + n. If the present age is x, then age n years ago = x – n. The ages in a ratio a: b will be ax and bx. If the current age is y, then 1/n of the age is y/n.

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Everything please helppppp!!
Soloha48 [4]

Answer:

Ok im, not 100% sure but the answer is for 1-10, 2-20, 3-40,  4-40

7 0
3 years ago
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Louis found two bakeries to provide bagels for his sub shop. The first bakery offers 350 bagels for $168.00 and the second baker
borishaifa [10]

Answer:

<h2>$352</h2>

Step-by-step explanation:

Find out the price of one bagel by dividing the price by the number of bagels:

350 Bagels = $168

1 Bagel = $0.48

475 Bagels = $209

1 Bagel = $0.44

0.48 > 0.44

This means the second bakery has the lower price.

Louis wants 800 bagels, so multiply the price by 800.

0.44 * 800 = $352

You can check it's lower by comparing it with the first bakery.

0.48 * 800 = $384

384 > 352

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3 years ago
For a moving object, the force acting on the object’s acceleration. When a force of 56 N acts on certain object, the acceleratio
ycow [4]

Answer:

force

Step-by-step explanation:

8 0
3 years ago
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Find the area of the shaded figure.
Gnoma [55]

Answer:

Its 20

Step-by-step explanation:

Because its correct

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5 0
3 years ago
Let f(x) = -5e^(-x/3)<br><br> Find f^(6) (1)
Luba_88 [7]

Let's take the first derivative:

f'(x) = (-5e^{-x/3})' = -5 \times (e^{-x/3})' = -5e^{-x/3} \times \left(-\dfrac{1}{3}\right) = \dfrac{5}{3}e^{-x/3}.

Notice that we can write this as:

f'(x) = -\dfrac{f(x)}{3}.

By taking the derivative of both sides n times, we get:

f^{(n+1)}(x) = -\dfrac{f^{(n)}}{3}.

This means that each time you take a derivative, a factor of -\dfrac{1}{3} will appear. So we conclude that:

f^{(n)}(x) = \left(-\dfrac{1}{3}\right)^nf(x).

Taking n=6 and x=1, we get:

f^{(6)}(1) = \left(-\dfrac{1}{3}\right)^6 f(1) = \dfrac{-5e^{-1/3}}{729} = -\dfrac{5}{729}e^{-1/3}.

So we finally get:

\boxed{-\dfrac{5}{729}e^{-1/3}}.

6 0
3 years ago
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