![\bf \begin{array}{ccccllll} &distance&rate(km/hr)&time(hrs)\\ &\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\\ A&d&60&t\\ B&600-d&v&t+3 \end{array}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Bccccllll%7D%0A%26distance%26rate%28km%2Fhr%29%26time%28hrs%29%5C%5C%0A%26%5Ctextendash%5Ctextendash%5Ctextendash%5Ctextendash%5Ctextendash%5Ctextendash%26%5Ctextendash%5Ctextendash%5Ctextendash%5Ctextendash%5Ctextendash%5Ctextendash%5Ctextendash%5Ctextendash%5Ctextendash%5Ctextendash%5Ctextendash%26%5Ctextendash%5Ctextendash%5Ctextendash%5Ctextendash%5Ctextendash%5Ctextendash%5Ctextendash%5Ctextendash%5Ctextendash%5Ctextendash%5C%5C%0AA%26d%2660%26t%5C%5C%0AB%26600-d%26v%26t%2B3%0A%5Cend%7Barray%7D)
![\bf \textit{meaning}\implies \begin{cases} d=(60)(t) \\ \quad \\ 600-d=(v)(t+3)\\ ------------\\ d=\boxed{60t}\qquad thus \\ \quad \\ 600-\boxed{60t}=v(t+3)\leftarrow \textit{solve for "t"} \end{cases}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bmeaning%7D%5Cimplies%20%0A%5Cbegin%7Bcases%7D%0Ad%3D%2860%29%28t%29%0A%5C%5C%20%5Cquad%20%5C%5C%0A600-d%3D%28v%29%28t%2B3%29%5C%5C%0A------------%5C%5C%0Ad%3D%5Cboxed%7B60t%7D%5Cqquad%20thus%0A%5C%5C%20%5Cquad%20%5C%5C%0A600-%5Cboxed%7B60t%7D%3Dv%28t%2B3%29%5Cleftarrow%20%5Ctextit%7Bsolve%20for%20%22t%22%7D%0A%5Cend%7Bcases%7D)
keep in mind, that "t" is the time when the train at A station, left towards B station
they met, at some time "t", and by the time that happened, train from A
which started 3 hours earlier, had already covered "d" distance,
whatever that is
and the train coming from B, covered, 600-d, or the difference
Answer:
BC = 10, AC= approximately 13.66 OR 5+5 √3
Step-by-step explanation:
Law of Sines
1/2 I’m just doing this answer because I need to finish setting up the account so it’s wrong my bad
Answer:
C
Step-by-step explanation:
The line of best fit is a linear function that is closest to all the points and shows the trend in the data. Since the data is going up ultimately, the slope of the line will be positive. Only B and C are options.
To find the best fit, draw a line through the center of the most points. This line will have as its y-intercept a value around 12 and a gentle slope. This means the answer choice is C.