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Schach [20]
3 years ago
5

1. Solve the equation. (1 point) 5x-1= 14

Mathematics
1 answer:
Rufina [12.5K]3 years ago
4 0

Answer: x = 3

Step-by-step explanation:

5x - 1 + 14 - original equation

5x = 15 - add 1 to both sides

x = 3 - divide both sides by 5

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If x2 + 6x + c = (x + d)2, then d
viktelen [127]

Answer:

d = 3

Step-by-step explanation:

Expand the right side and compare the coefficients of like terms

x² + 6x + c = x² + 2dx + d²

For the 2 sides to be equal then coefficients of like terms must be equal

compare coefficients of x- terms, then

2d = 6 ⇒ d = 3



8 0
3 years ago
Read 2 more answers
A company produces a certain product, and each unit of this product may have 3 different types of defects. Let Di, D2,Ds represe
Stella [2.4K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a) 0.88

b) 0.02

c) 0.01

d) 0.99

Step-by-step explanation:

Step one: State the given parameters

            P(D_{1} ) = 0.12                                   P(D_{2} ) = 0.07

           P(D_{3} ) = 0.05                                    P (D_{1} U D_{2} ) = 0.13

          P(D_{1}n D_{2}n D_{3}) = 0.01                        P(D_{1} U D_{3}) = 0.14

Step 2 : Obtain the probability that a unit does not have a type 1 defect

         P(\frac{}{D_{1} }) =  1 -P(D_{1} )

                    = 1 - 0.12

                    = 0.88  

Step 3 : Obtain the probability that a unit has both type 2 and 3 defect?

          The probability of the unit having both type 2 and type 3 defect is denoted as P(D_{2} n D_{3} )

   This is calculated as

                    P(D_{2}n D_{3}) =P(D_{2} ) + P(D_{3}) - P(D_{2} U D_{3})\\\\                          = 0.07 + 0,05 - 0.13

                    =   0.02

Therefore P(D_{2} n D_{3} ) = 0.02

Step 4 : Obtain the probability that the unit has both a type 2 and type 3 ,but not a type 1 defect

                  Let P(\frac{}{D_{1}} n D_{2} n D_{3} ) denote the  probability that the unit has both a type 2 and type 3 ,but not a type 1 defect.

This can be calculated as follows :

                      P(\frac{}{D_{1}} n D_{2} n D_{3} ) = P(D_{2} n D_{3}) - P(D_{1} n D_{2}nD_{3})

                                               =   0.02 - 0.01

                                               =  0.01

Step 4 : Obtain the probability that a unit has at most two defects

               P(at most 2 defects)  = 1 - P(all three defects)

                                                  = 1- P(D_{1} n D_{2}nD_{3})

                                                  =  1 - 0.01

                                                  = 0.99

7 0
3 years ago
Look at the orange points on the graph. If the x-values a and c are 1 unit apart, how are the y-values b and d related?
ankoles [38]

Answer:

multiply 2 by b to get d

Step-by-step explanation:

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3 years ago
Find the value of the variable 10 45
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Answer:

35.

Step-by-step explanation:

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4 years ago
Write a mixed number that is greater than 3 but less than 4
uysha [10]
3 1/2 is one answer  Hope this helps! Hit that thanks button and rate 5 stars for brainliest answer! Have a nice day :)
6 0
3 years ago
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