<span>If points of a region represent equally-likely outcomes, then you can find probabilities by comparing areas would be true.</span>
1 gal + 2 qt + 3 pts
1 gal + 3 qt + 7 pts
1 gal + 3 qt + 3 pts
----------------------------add
3 gal + 8 qt + 13 pts
1 gal = 4 qts
1 gal = 8 pts
1 pt = 1/2 qt
13 pts = 6.5 qts
now we have 3 gal + (8 + 6.5) = 3 gal + 14.5 qts
12 qts = 3 gal
now we have : 6 gal + 2.5 qts or 6 gal + 2 qts + 1 pt <=== answer
Answer:
The number of 32 Gigabit keys that can be fitted on the hard drive is 375.
Step-by-step explanation:
The question is:
If my hard drive has a capacity of 1.5 Terabytes, how many 32 Gigabit keys can fit on that hard drive?
Solution:
1 Terabyte = 8000 Gigabits
Then 1.5 Terabytes in Gigabits is:
1.5 Terabytes = (8000 × 1.5) Gigabits
= 12000 Gigabits
One key is of 32 Gigabits.
Compute the number of 32 Gigabit keys that can be fitted on the hard drive as follows:
Thus, the number of 32 Gigabit keys that can be fitted on the hard drive is 375.
Because vol= length x width x height , and assuming that the height is 11.5 because breadth means width but you already have a width then, vol= 11.5 x 7.4 x 11.5, vol = 978.65
Answer:
4
Step-by-step explanation:
ΔABC is congruent with ΔDEF. That means the corresponding sides are congruent.
Look at the order of the letters. EF are the last two letters of ΔDEF. So this corresponds with the last two letters of ΔABC. Therefore, EF ≅ BC.
EF ≅ BC
x² + 8x = 48
x² + 8x − 48 = 0
(x + 12) (x − 4) = 0
x = -12 or 4
Since x can't be negative, x = 4.
