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galben [10]
3 years ago
7

What did you have to look at it in order to correctly measure the amount of water in the graduated cylinder?

Chemistry
2 answers:
Zielflug [23.3K]3 years ago
6 0

Answer:

Water sticks to the walls of the graduated cylinder, but only on the sides and not the middle. When students look at the surface, the water level is not straight.

Explanation:

meninges

meniscus

measles

metatarsle

DerKrebs [107]3 years ago
3 0
To make it more clear for you, you have to look at bottom the meniscus. :) Rate if this helps
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What is the k expression for this reaction? plz help !
just olya [345]

Answer:

K = [HI]² / [H₂] [I₂]

Explanation:

To write the expression of equilibrium constant, K, it is important that we know how to obtain the equilibrium constant.

The equilibrium constant, K for a given reaction is simply defined as the ratio of the concentration of the products raised to their coefficient to the concentration of the reactants raised to their coefficient. Thus, the equilibrium constant is written as follow:

K = [Product] / [Reactant]

Now, we shall determine the equilibrium constant for the reaction given in the question above. This can be obtained as illustrated below:

H₂(g) + I₂(g) —> 2HI (g)

K = [HI]² / [H₂] [I₂]

6 0
3 years ago
A geological sample is found to have a Pb-206/U-238 mass ratio of 0.337/1.00. Assuming there was no Pb-206 present when the samp
nikdorinn [45]

Answer:

2.1x10⁹ years

Explanation:

U-238 is a radioactive substance, which decays in radioactive particles. It means that this substance will lose mass, and will form another compound, the Pb-206.

The time need for a compound loses half of its mass is called half-life, and knowing the initial mass (mi) and the final mass (m) the number of half-lives passed (n) can be found by:

m = mi/2ⁿ

The mass of Pb-206 will be the mass that was lost by U-238, so it will be mi - m. Thus, the mass ration can be expressed as:

(mi-m)/m = 0.337/1

mi - m = 0.337m

mi = 1.337m

Substituing mi in the expression of half-life:

m = 1.337m/2ⁿ

2ⁿ = 1.337m/m

2ⁿ = 1.337

ln(2ⁿ) = ln(1.337)

n*ln(2) = ln(1.337)

n = ln(1.337)/ln2

n = 0.4190

The time passed (t), or the age of the sample, is the half-life time multiplied by n:

t = 4.5x10⁹ * 0.4190

t = 1.88x10⁹ ≅ 2.1x10⁹ years

5 0
3 years ago
Which of the following is a nonrenewable resource?
Dahasolnce [82]

The answer is D, coal is a nonrenewable resource.

4 0
3 years ago
Read 2 more answers
2. A 10.0 g ice cube, initially at 0.0ºC, is melted in 100.0 g of water that was initially 20.0ºC. After the ice has melted, the
arlik [135]

Answer:

The heat lost  by the water  Q_{water}  = 3.8 KJ

The heat gain by ice  Q_{ice} = 228.76 J

The heat required to melt the ice Q_{melt} = 3340 J

Explanation:

Mass of ice cube m_{ice} = 10 gm

Initial temperature of ice cube T_{ice} = 0 °c

Mass of water m_{water} = 100 gm

Initial temperature of water T_{w} = 20 °c

Final temperature of mixture T_{f} = 10.93 °c

(a). Total heat lost by the water Q_{water}  =  m_{water} C_{w} ( T_{f} - T_{w} )

⇒ Q_{water}  = 100 × 4.184 (20 - 10.93)

⇒ Q_{water}  = 3.8 KJ

This is the heat lost  by the water.

(b). Heat gained by the ice cube Q_{ice} = m_{ice} C_{ice} (T_{f} - T_{ice}  )

⇒ Q_{ice} = 10 × 2.093 × ( 10.93 - 0)

⇒ Q_{ice} = 228.76 J

This is the heat gain by ice.

(C). Heat required to melt the ice Q_{melt} = m_{ice} × Latent Heat

⇒ Q_{melt} = 10 × 334

⇒ Q_{melt} = 3340 J

This is the heat required to melt the ice.

7 0
3 years ago
(science) <br> hurry help!!<br><br> All commonly abused drugs are illegal.<br><br> true or false
Lubov Fominskaja [6]

Answer:

False

Explanation:

Many abused drugs are prescription drugs.

8 0
3 years ago
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