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Lunna [17]
3 years ago
8

(science) hurry help!! All commonly abused drugs are illegal. true or false

Chemistry
2 answers:
Lubov Fominskaja [6]3 years ago
8 0

Answer:

False

Explanation:

Many abused drugs are prescription drugs.

Radda [10]3 years ago
5 0
False a lot of abused drugs are prescription
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The small part of the nucleus where ribosomal subunit formation takes place
vaieri [72.5K]
The small part of the nucleus where ribosomal subunit formation takes place is called the nucleolus. This structure is found in eukaryotic cells and takes up about 25 percent of the volume of the nucleus. This structure is said to be the brain of the nucleus. It is made up of ribobucleic acids or the RNA and proteins. Its primary function is to transcript the ribosomal RNA (rRNA) and to combine these with the proteins resulting to the formation of an incomplete ribosome.  Since it is closely related to a chromosomal matter of a cell and important in the production of ribosome, this structure is correlated to be one of the cause of a number of diseases.
3 0
4 years ago
Classify each of the following as an exothermic or endothermic reaction:
serious [3.7K]
<h3><u>Answer;</u></h3>

1) 2H2(g)+O2(g)⟶Δ2H2O(g)+483.6kJ  - Exothermic

2) 6CO2(g)+6H2O(l)+15000kJ⟶C6H12O6(aq)+6O2(g)  - Exothermic

3) 2Al(s)+Fe2O3(s)⟶Al2O3(s)+2Fe(s)+850kJ - Exothermic

<h3><u>Explanation</u>;</h3>
  • Exothermic Reaction is a chemical reaction in which heat is given out is known as exothermic reaction, while, and endothermic Reaction is a chemical reaction in which heat energy is absorbed is known as endothermic reaction.
  • The reaction between carbon dioxide and water is an example of an exothermic reaction. When most gases dissolve in solution, the process is exothermic meaning that heat is released as the gas dissolves
  • The reduction of ferric oxide by aluminium is highly exothermic and therefore the iron formed will be in the molten state.
6 0
4 years ago
Given an initial cyclopropane concentration of 0.00560 m, calculate the concentration of cyclopropane that remains after 1.50 ho
maria [59]

<span>We can solve this problem by assuming that the decay of cyclopropane follows a 1st order rate of reaction. So that the equation for decay follows the expression:</span>

A = Ao e^(- k t) 

Where,

A = amount remaining at time t = unknown (what to solve for) <span>
Ao = amount at time zero = 0.00560 M </span><span>
<span>k = rate constant
t = time = 1.50 hours or 5400 s </span></span>

The rate constant should be given in the problem which I think you forgot to include. For the sake of calculation, I will assume a rate constant which I found in other sources:

k = 5.29× 10^–4 s–1                     (plug in the correct k value)

<span>Plugging in the values in the 1st equation:</span>

A = 0.00560 M * e^(-5.29 × 10^–4 s–1 * 5400 s )

A = 3.218 <span>× 10^–4 M           (simplify as necessary)</span>

8 0
3 years ago
If a temperature increase from 12.0 ∘c to 22.0 ∘c doubles the rate constant for a reaction, what is the value of the activation
Alex73 [517]

Answer: 48,501 J/mol


Explanation:


1) Action barrier = activation energy = Ea


2) Data:


i) T₁ = 12°C = 12 + 273.15 K = 285.15K

ii) T₂ = 22°C = 22 + 273.15 K = 295.15 K

iii) rate constant = k: k₂ / k₁ = 2


iv) Ea = ?


3) Formula:


Arrhenius' law gives the relationship between the constant of reaction and the temperature:


k=Ae^{-\frac{Ea}{RT}}


4) Solution


By arranging the formula, you get:


㏑[k₂/k₁] =Ea/R [1/T₁ - 1/T₂]


Replace k₂ = 2k₁; T₁ = 285.15; and T₂ = 295.15


ln[2] = Ea/8.314 J/K mol × [1/285.15 - 1/295.15]K


Ea = ln [2] × 8.314 J/K mol / [1.18818×10⁻⁴K] = 48,501 J/mol





6 0
4 years ago
A neutral atom has the following electron configuration: What is the chemical symbol for the atom? How many electrons does the a
tiny-mole [99]

Answer:

pls the image didn't come

Explanation:

ols the. atom's image didn't appear

3 0
3 years ago
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