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8_murik_8 [283]

3 years ago

14

Calculate Δ H ∘ in kilojoules for the reaction of ammonia (Δ H ∘ f =−46.1 kJ/mol) with O 2 to yield nitric oxide NO (Δ H ∘ f =91

.3 kJ/mol) and H 2 O(g) (Δ H ∘ f =−241.8 kJ/mol) , a step in the Ostwald process for the commercial production of nitric acid.

1 answer:

Vitek1552 [10]3 years ago

7 0

Ummmmmmm......... im in 6th grade and i do not understand 1 bit of this, but i tried, sorry! :)

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Gemiola [76]

Answer:

Climate

Explanation:

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6 0

3 years ago

Give the percent yield when 28.16 g CO2 are formed from the reaction of 8.000 moles of C8H18 with 4.000 moles of O2.

HACTEHA [7]

<span>The correct answer between all the choices given is the 4th choice or letter D. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.</span>

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3 years ago

The product of the nuclear reaction in which 40Ar is subjected to neutron capture followed by alpha emission is ________. The pr

Orlov [11]

Answer:

37S

Explanation:

Radioactivity is the spontaneous emission of particles and / or electromagnetic radiation by unstable atomic nuclei leading to their disintegration.

We have two main types of radioactivity: radioactive decay and artificial transmutation.

In radioactive decay ( natural radioactivity ), a naturally occurring radioactive element like Uranium-238 disintegrates or decays into more stable isotopes with the emission of particles and/or radiation.

23892U = 23490Th + 42He

Artificial transmutation is the collision of two particles where one particle captures the other used to bombard it. There is subsequent production of isotopes similar or different from the bombarded particle. Neutrons, alpha particles ( helium nucleus ), electrons, protons can be used to bombard elements.

147N + 42He = 178O + 11P

For the above question which is artificial transmutation, the reaction equation is

4018Ar + 10n = 3716S + 42He

So, the neutron capture by Argon-40 will produce a radioisotope Sulphur-37 with the emission of an alpha particle.

5 0

3 years ago

Consider the combustion reaction for octane (C8H18), which is a primary component of gasoline.

lesya692 [45]

Answer:

$n_{CO_2}=1.93 gCO_2$

Explanation:

Hello,

In this case, considering the given chemical reaction, we can use the molar mass of octane (114.23 g/mol) and the 2:16 molar ratio with carbon dioxide to compute the emitted moles of CO2 to the atmosphere via the following stoichiometric procedure:

$n_{CO2}=27.6gC_8H_{18}*\frac{1molC_8H_{18}}{114.23gC_8H_{18}} *\frac{16molCO_2}{2molC_8H_{18}} \\\\n_{CO_2}=1.93 gCO_2$

Which also corresponds to the following mass:

$m_{CO_2}=1.93molCO_2*\frac{44gCO_2}{1molCO_2} \\\\m_{CO_2}=85.0gCO_2$

Best regards.

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3 years ago

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