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8_murik_8 [283]

2 years ago

14

Calculate Δ H ∘ in kilojoules for the reaction of ammonia (Δ H ∘ f =−46.1 kJ/mol) with O 2 to yield nitric oxide NO (Δ H ∘ f =91

.3 kJ/mol) and H 2 O(g) (Δ H ∘ f =−241.8 kJ/mol) , a step in the Ostwald process for the commercial production of nitric acid.

1 answer:

Vitek1552 [10]2 years ago

7 0

Ummmmmmm......... im in 6th grade and i do not understand 1 bit of this, but i tried, sorry! :)

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Choose the aqueous solution below with the lowest freezing point. These are all solutions of nonvolatile solutes and you should

atroni [7]

Answer:

$(NH_4)_3PO_4$ 0.075 m solution has the lowest freezing point.

Explanation:

Depression in freezing point is given by:

$\Delta T_f=T-T_f$

$\Delta T_f=K_f\times m$

$\Delta T_f=iK_f\times \frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Mass of solvent in Kg}}$

where,

$\Delta T_f$ =Depression in freezing point

$K_f$ = Freezing point constant of solvent

1 - van't Hoff factor

m = molality

According question, molality of all the solutions are same and are in prepared with same solvent. So, values of molality and $K_f$ will remain the same and will not effect the freezing point of the solution.

The lowering in freezing point will now depend upon van't Hoff factors of the solutions. Higher the value of van'Hoff factor more will be the lowering in freezing point of the solution.

The van't Hoff factor of $KNO_2$ solution = $i_1=2$

The van't Hoff factor of $LiCN$ solution = $i_2=2$

The van't Hoff factor of $(NH_4)_3PO_4$ solution = $i_3=4$

The van't Hoff factor of $NaI$ solution = $i_4=2$

The van't Hoff factor of $NaBrO_3$ solution = $i_5=2$

The solution of ammonium phosphate has the highest values of van't Hoff factor which will result in maximum lowering of the freezing point of the solution.

Hence, $(NH_4)_3PO_4$ 0.075 m solution has the lowest freezing point.

4 0

3 years ago

Read 2 more answers

calculate density of a rectangular solid, which has a mass of 25.71 g. It is 2.30 cm long, 4.01 cm wide and 1.82 cm high.

Levart [38]

Density is a property of the substances that is obtained by dividing its mass by the volume. For a rectangular solid, the volume may be solved by the following equation,

V = L x W x H

Substituting the given values for the dimension,

V = (2.30 cm) x (4.01 cm) x (1.82 cm) = 16.78786 cm³

Calculating for the density,

Density = mass / volume

Density = 25.71 cm / <span>16.78786 cm³ = 1.53 grams per cm</span>³

Thus, the density of the given solid is approximately 1.53 grams per cm³.

5 0

3 years ago

In the following equation, what are the reactants: NaHCO3 + HCl? NaCl + H2O + CO2

elena55 [62]

I believe the correct answer from the choices listed above is option A. The reactant for the given chemical reaction would be NaHCO3 and HCl. <span>A </span>reactant<span> is a substance that changes in a chemical reaction. It is the starting material in a reaction. Hope this answers the question.</span>

6 0

3 years ago

Read 2 more answers

How many sigma bonds in a single bond

Katarina [22]

Answer:

single bond= 1 sigma bond

so basically 1

Explanation:

Usually, all bonds between atoms in most organic compounds contain one sigma bond each. If it is a single bond, it contains only sigma bond. Multiple bonds (double and triple), however, contains sigma and pi bonds. Double bonds have one each, and triple bonds have one sigma bond and two pi bonds

8 0

3 years ago

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How many moles are in 3.4 x 10-7 grams of Silicon dioxide, SiO2?

Varvara68 [4.7K]

Answer:

Number of moles = 0.057 × 10⁻⁷ mol

Explanation:

Given data:

Mass of SiO₂ = 3.4 × 10⁻⁷ g

Number of moles = ?

Solution:

Number of moles = mass/molar mass

Molar mass of SiO₂ = 60 g/mol

by putting values,

Number of moles = 3.4 × 10⁻⁷ g / 60 g/mol

Number of moles = 0.057 × 10⁻⁷ mol

8 0

3 years ago