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Pie
3 years ago
14

How many moles of hydrogen are in 4.70 moles of C12H22O11

Chemistry
1 answer:
Sphinxa [80]3 years ago
8 0

Answer:

103.4 moles of hydrogen

Explanation:

Given data:

Moles of C₁₂H₂₂O₁₁ = 4.70 mol

Number of moles of hydrogen present = ?

Solution:

one mole of C₁₂H₂₂O₁₁  contain 22 moles of hydrogen. Thus in order to determine total number of moles in 4.70 moles of C₁₂H₂₂O₁₁ we will multiply the 22 moles of hydrogen with 4.70 moles of C₁₂H₂₂O₁₁.

1 mole of C₁₂H₂₂O₁₁ = 22 moles of Hydrogen

4.70  × 22 moles

103.4 moles of hydrogen

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How many electrons, protons and neutrons are in the element sodium
scZoUnD [109]

Answer:

The element sodium has 12 neutrons, 11 electrons and 11 protons. The number of electrons and protons come from the element's atomic number, which is same 11. The number of neutrons can be found by subtraction of the atomic number from sodium's atomic mass of twenty three.

Explanation:

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5 0
3 years ago
Is this statement true or false? Ammonia is a base. A. True B. False
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It is true.
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6 0
4 years ago
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A sample of propane, C3H8, contains 14.6 moles of carbon atoms. How many total moles of atoms does the sample contain
seraphim [82]

Answer:

161 atoms

Explanation:

A sample of propane, C3H8, contains 14.6 moles of carbon atoms. How many total moles of atoms does the sample contain

every molecule of propane contains 3+8=11 atoms

so

14.6 moles contain 14.6 X 11 = 161 atoms

4 0
3 years ago
You are asked to write observations about a 100g sample of Nitrogen-16 before it decays, but you're running late. In order to ma
san4es73 [151]

Answer:

You cannot make observations if you are 57 seconds late into the lab.

Explanation:

The atomic nucleus can split by decay into 2 or more particles as a result of the instability of its atomic nucleus due to the fact that radioactive elements possess an unstable atomic nucleus.

Now, the primary particles which are emitted by radioactive elements in order to make them decay are alpha, beta & gamma particles.

The half life equation is;

N_t = N₀(½)^(t/t_½)

Where:

t = duration of decay

t_½ = half-life

N₀ = number of radioactive atoms initially

N_t = number of radioactive atoms remaining after decay over time t

We are given;

t = 57 secs

N₀ = 100 g

Now, half life of Nitrogen-16 from online sources is 7.2 seconds. t_½ = 7.2

Thus;

N_t = 100(1/2)^(57/7.2)

N_t = 0.4139g

We are told that In order to make observations, you require at least .5g of material.

The value of N_t you got is less than 0.5g, therefore you cannot make observations if you are 57 seconds late.

5 0
3 years ago
A compound consists of 75% magnesium and 25% oxygen. Find the empirical formula.
laila [671]
<h2>Answer:</h2>

% Composition of elements:

  • Magnesium = 75%
  • Oxygen = 25%

Atomic mass of given elements:

  • Magnesium = 24 g
  • Oxygen = 16 g

Now, divide % composition by Atomic mass:

\footnotesize\implies Mg = \dfrac{\% \:  Composition}{Atomic  \: mass} =  \dfrac{75}{24}  =  \bf 3.125

\footnotesize\implies O = \dfrac{\% \:  Composition}{Atomic  \: mass} =  \dfrac{25}{16}  =  \bf 1.5625

Simplest Ratio:

\footnotesize\implies Mg  =  \dfrac{3.125}{1.5625}  = 2

\footnotesize\implies O  =  \dfrac{1.5625}{1.5625} = 1

Empirical Formula:

\footnotesize\implies \underline{ \boxed{ \red{ \bf Empirical \:  Formula = Mg_2O}}}

8 0
3 years ago
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