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creativ13 [48]
3 years ago
12

You are asked to write observations about a 100g sample of Nitrogen-16 before it decays, but you're running late. In order to ma

ke observations, you require at least .5g of material. Can you make observations if you are 57 seconds late to the lab?
Chemistry
1 answer:
san4es73 [151]3 years ago
5 0

Answer:

You cannot make observations if you are 57 seconds late into the lab.

Explanation:

The atomic nucleus can split by decay into 2 or more particles as a result of the instability of its atomic nucleus due to the fact that radioactive elements possess an unstable atomic nucleus.

Now, the primary particles which are emitted by radioactive elements in order to make them decay are alpha, beta & gamma particles.

The half life equation is;

N_t = N₀(½)^(t/t_½)

Where:

t = duration of decay

t_½ = half-life

N₀ = number of radioactive atoms initially

N_t = number of radioactive atoms remaining after decay over time t

We are given;

t = 57 secs

N₀ = 100 g

Now, half life of Nitrogen-16 from online sources is 7.2 seconds. t_½ = 7.2

Thus;

N_t = 100(1/2)^(57/7.2)

N_t = 0.4139g

We are told that In order to make observations, you require at least .5g of material.

The value of N_t you got is less than 0.5g, therefore you cannot make observations if you are 57 seconds late.

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Eddie is going to do an experiment to find out which freezes more easily—distilled water or salt water. In what order should he
mel-nik [20]

1. Make a Prediction

2. Fill both beakers with water

3. Dissolve salt in one of the beakers

4. Place both in the freezer and observe

5. Write a report

(Always make the prediction first! That's a hypothesis!)

4 0
4 years ago
Read 2 more answers
Calculate the grams of solute in each of the following solution: 278 mL of 0.038 M Fe2(SO4)3
Goryan [66]

Answer:  4.22 grams of solute is there in 278 ml of 0.038 M Fe_2(SO_4)_3

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n}{V_s}

where,

n = moles of solute

V_s = volume of solution in L

Now put all the given values in the formula of molality, we get

0.038M=\frac{n}{0.278L}

n=0.0105mol  

mass of  Fe_2(SO_4)_3 = moles\times {\text {Molar Mass}}=0.0105\times 399.88g/mol=4.22g

Thus 4.22 grams of solute is there in 278 ml of 0.038 M Fe_2(SO_4)_3

3 0
3 years ago
Is methylene chloride more or less dense than water?
horsena [70]
Methylene chloride is less dense than water
3 0
3 years ago
Which statements true about the total mass of the reactants during a chemical change? (5 points)
Lapatulllka [165]
It is greater than the total mass
5 0
3 years ago
U-235 undergoes many different fission reactions. For one such reaction, when U-235 is struck with a neutron, Ce-144 and Sr-90 a
Lostsunrise [7]

Explanation:

A nuclear fission reaction is defined as the reaction in which a heavy nucleus splits into small nuclei along with release of energy.

The given reaction is ^{235}_{92}U + ^{1}_{0}n \rightarrow ^{144}_{58}Ce + ^{90}_{38}Sr + x^{1}_{0}n + y^{0}_{-1}\beta

Now, we balance the mass on both reactant and product side as follows.

         235 + 1 = 144 + 90 + (x \times 1) + (y \times 0)

           236 = 234 + x

            x = 236 -234

               = 2

So, now we balance the charge on both reactant and product side as follows.

              92 + 0 = 58 + 38 + (x \times 0) + (y \times -1)

                92 = 96 - y

                  y = 4

Thus, we can conclude that there are 2 neutrons and 4 beta-particles are produced in the given reaction.

Therefore, reaction equation will be as follows.

           ^{235}_{92}U + ^{1}_{0}n \rightarrow ^{144}_{58}Ce + ^{90}_{38}Sr + 2^{1}_{0}n + 4^{0}_{-1}\beta

8 0
3 years ago
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