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creativ13 [48]
3 years ago
12

You are asked to write observations about a 100g sample of Nitrogen-16 before it decays, but you're running late. In order to ma

ke observations, you require at least .5g of material. Can you make observations if you are 57 seconds late to the lab?
Chemistry
1 answer:
san4es73 [151]3 years ago
5 0

Answer:

You cannot make observations if you are 57 seconds late into the lab.

Explanation:

The atomic nucleus can split by decay into 2 or more particles as a result of the instability of its atomic nucleus due to the fact that radioactive elements possess an unstable atomic nucleus.

Now, the primary particles which are emitted by radioactive elements in order to make them decay are alpha, beta & gamma particles.

The half life equation is;

N_t = N₀(½)^(t/t_½)

Where:

t = duration of decay

t_½ = half-life

N₀ = number of radioactive atoms initially

N_t = number of radioactive atoms remaining after decay over time t

We are given;

t = 57 secs

N₀ = 100 g

Now, half life of Nitrogen-16 from online sources is 7.2 seconds. t_½ = 7.2

Thus;

N_t = 100(1/2)^(57/7.2)

N_t = 0.4139g

We are told that In order to make observations, you require at least .5g of material.

The value of N_t you got is less than 0.5g, therefore you cannot make observations if you are 57 seconds late.

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3 years ago
The pressure inside a gas cylinder is 3,506 mmHg. How many atmospheres of pressure is the gas exerting on the cylinder?
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Below are the choices:

a)0.2168 atm 
<span>b)4.613 atm </span>
<span>c)34.60 atm </span>
<span>d467.4 atm 
</span>
1 atm = 760mmHg : Therefore: 
<span>3,506mmHg = 3,506/760 = 4.613 atm 
</span>B is correct answer. 

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
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