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ollegr [7]
3 years ago
6

The tendency of an element to react is closely related to

Chemistry
2 answers:
umka2103 [35]3 years ago
6 0

The tendency  of an element  to react  is closely  related to  the number  of valence   electrons in atoms of the element (answer  C).


   <u><em>Explanation</em></u>

<em><u> </u></em>Valence  electrons  are outer  shell  electrons  of an atom.They govern the bonding   behavior  of  an element.


 when element react  to form compound, valence  electron  are involved.

Valence electrons  are involved in a reaction either by sharing  among   atoms or may be  transferred  from one  atom  to another.

For example in  formation  of NaCl bond there  is transfer of  valence electron between  Na  and Cl. Na  donate 1 valence electron  while Cl accept 1 electron to form NaCl

Shtirlitz [24]3 years ago
5 0
<span>Answer: c. the number of valence electrons in atoms of the element

The valence electrons determine how it would bond and if it would react.</span>
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Answer:

sodium chloride—is NaCl.

Explanation:

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The molar heat capacity of ethane is represented in the temperature range 298 K to 400 K by the empirical expression Cp,m in J K
BabaBlast [244]

Answer:

-88.66 kJ/mol

Explanation:

The expressions of heat capacity (Cp,m) for C(s) and for H₂(g) are:

C(s):  Cp,m/(J K-1 mol-1) = 16.86 + (4.77T/10³) - (8.54x10⁵/T²)

H₂(g): Cp,m/(J K-1 mol-1) = 27.28 + (3.26T/10³) + (0.50x10⁵/T²)

Cp = A + BT + CT⁻²

For the Kirchoff's Law:

ΔHf = ΔH°f + \int\limits^{T2}_{T1} {DCp(T)} \, dT

Where ΔH°f is the enthalpy at 298 K, T1 is 298 K, T2 is the temperature given (373 K), and DCp is the variation of Cp (products less reactants). ΔH°f  for ethene is -84.68 kJ/mol and the reaction is:

2C(s) + 3H₂(g) → C₂H₆

So, DCp:

dA = A(C₂H₆) - [2xA(C) + 3xA(H₂)] = 14.73 - [2x16.86 + 3x27.28] = -100.83

dB = B(C₂H₆) - [2xB(C) + 3xB(H₂)] = 0.1272 - [2x4.77x10⁻³ + 3x3.26x10⁻³] = 0.10788

dC = C(C₂H₆) - [2xC(C) + 3xC(H₂)] = 0 - (2x(-8.54x10⁵) + 3x0.50x10⁵) = 15.58x10⁵

dCp = -100.83 + 0.10788T + 15.58x10⁵T⁻²

\int\limits^{373}_{298} {-100.83 + 0.10788T + 15.58x10^5T^{-2}} \, dT = -3796.48 J/mol = -3.80 kJ/mol (solved by a graphic calculator)

ΔHf = -84.68 - 3.80

ΔHf = -88.66 kJ/mol

7 0
3 years ago
In a sealed gas-liquid system at constant temperature, eventually...?
SOVA2 [1]
<h2>Let us study about it .</h2>

Explanation:

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Condensation

It is the process of converting  vapors back into liquid state .

  1. Suppose if we have a sealed container and we are supplying it with no or little heat , we will see that as we increase heat , the particles starts moving faster .
  2. When they move they also colloide and transfer energies .
  3. The kinetic energies of certain molecule increase to an extent that they leave the other particles and escape in atmosphere .
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It is seen that  a equilibrium is reached when "rate of evaporation becomes equal to rate of condensation ".

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Answer:

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If the melting point of the mixture of A and C is the same as the pure substances, we can deduce that they are the same substances, also because the melting point when a substance is pure is just 1 or 2 ºC like in this case.

So in a Mixture of B and C is going to be like the first case of the mixture among A and B, because the B substance is the impurity.

3 0
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