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guajiro [1.7K]
2 years ago
10

Glenn ate 2 apples a day for a week. In addition to the apples, he ate 3 pears during the week. write the expression that shows

how many pieces of fruit he ate during the week.
Mathematics
1 answer:
Mama L [17]2 years ago
7 0

Answer:

17 pieces of fruit in total

Step-by-step explanation:

2x7=14+3=17

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What is the length of the hypotenuse of the triangle?
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Answer:

<em>8.1</em><em> </em><em>ft</em>

Step-by-step explanation:

hyp² = side² + side²

hyp² = 7² + 4²

hyp² = 49 + 16

hyp² = 65

hyp = sqrt of 65

hyp = 8.1 ft

<em>PLEASE</em><em> </em><em>DO MARK</em><em> </em><em>ME AS</em><em> </em><em>BRAINLIEST UWU</em><em> </em>

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25^2

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Step-by-step explanation:

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Among all monthly bills from a certain credit card company, the mean amount billed was $465 and the standard deviation was $300.
Fynjy0 [20]

Answer:

0.02% probability that the average amount billed on the sample bills is greater than $500.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 465, \sigma = 300, n = 900, s = \frac{300}{\sqrt{900}} = 10.

What is the probability that the average amount billed on the sample bills is greater than $500?

This probability is 1 subtracted by the pvalue of Z when X = 500. So

Z = \frac{X - \mu}{s}

Z = \frac{500 - 465}{10}

Z = 3.5

Z = 3.5 has a pvalue of 0.9998.

So there is a 1-0.9998 = 0.0002 = 0.02% probability that the average amount billed on the sample bills is greater than $500.

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Answer:

Step-by-step explanation:

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