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liq [111]
3 years ago
10

Referring to y = x + 2, the set of values assigned to x is called the —

Mathematics
2 answers:
sleet_krkn [62]3 years ago
7 0

x is called the domain of the problem.

I hope this helps.

please make me brainliest.♥

seraphim [82]3 years ago
3 0

Answer:- The set of values assigned to s is called the domain.


Explanation :-

For the given equation y= x+2, x is a independent variable where y is a dependent variable .

The given equation representing a function y=f(x)=x+2

We know that for every function f(x), the set of values assigned to x is called the domain and the set of corresponding outputs y for each value of x  is called the range.



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PLEASEEE HELP ! I WOULD APPRECIATE IT VERY MUCH :)
azamat

hi!

so the original equation is (x^2 -121) / x+ 11.

Those two equations look similar...

well, we know that the top equation looks like a^2 - b^2, and that equation iis equivalent to this equation: (a+b)(a-b).

So if we factor that out, we get:

( (x + 11) * (x-11) )/ (x + 11)

we can cancel the x+11 on the top and the x+11 on the bottom out.

that leaves us with x-11.

Hope this helped!

8 0
3 years ago
EASY POINTS:
iVinArrow [24]

Answer: -750ft

Step-by-step explanation: -450+-300=-750

3 0
3 years ago
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If answer is correct I will mark as brainliest.
Serga [27]

Answer:

c

Step-by-step explanation:

8 0
3 years ago
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Assume the competing hypotheses take the following form: H0: µ1 – µ2 = 0, HA: µ1 – µ2 ≠ 0, where µ1 is the population mean for p
DedPeter [7]

Answer:

t=\frac{\bar x_1- \bar x_2}{\sqrt{\frac{s_1^2}{n_1} +\frac{s_2^2}{n_2} } }

Step-by-step explanation:

H0: µ1 – µ2 = 0

HA: µ1 – µ2 ≠ 0

We have given,

The population variances are not known and cannot be assumed equal.

The test statistic for the test is

t=\frac{\bar x_1- \bar x_2}{\sqrt{\frac{s_1^2}{n_1} +\frac{s_2^2}{n_2} } }

Where,

\bar x_1 = sample meaan of population 1

\bar x_2 = sample mean of population 2

n_1 = sample size of population 1

n_2 = sample size of population 2

Therefore, this is the test

t=\frac{\bar x_1- \bar x_2}{\sqrt{\frac{s_1^2}{n_1} +\frac{s_2^2}{n_2} } }

7 0
3 years ago
What is the surface area of the triangular prism Not drawn to scale 2001 2376 2592 4320
liq [111]

Answer:

Option B. 2376 Square feet

Step-by-step explanation:

The following were obtained obtained from the question:

Base (B) = 24ft

Length (L) = 40ft

Height (H) = 9ft

Slant height (S) = 15ft

Surface Area (A) =?

The surface area (A) for triangular prism is given below:

A = BH + 2LS + LB

Where:

B is the Base

L is the Length

H is the Height

S is the Slant Height

A is the Surface Area

Using the above equation, the surface area can be obtained as follow:

A = BH + 2LS + LB

A = (24x9) + (2x40x15) + (40x24)

A = 216 + 1200 + 960

A = 2376 ft2

7 0
3 years ago
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