Answer:
B. f(x) = 3x + 26;26≤ y ≤ 35
Step-by-step explanation:
This would be a linear equation in the form
y= mx+b
where b is the initial value (or 26 clients)
m is the slope, or the amount they want to increase by each week
y = 3x+26
Let x =0
y = 26 or what we start with
Let x =3, or be week 4 (we started with x= 0)
y = 3*3 +26
y =9+26
y= 35
35% because 35% of 80 is 28
2m+12=22
-12 -12
2m=10
/2 /2
M=5
Answer:
![x^2 + 2xy + y^2](https://tex.z-dn.net/?f=x%5E2%20%2B%202xy%20%2B%20y%5E2)
Step-by-step explanation:
![(x+y)^2 = (x+y)(x+y)](https://tex.z-dn.net/?f=%28x%2By%29%5E2%20%3D%20%28x%2By%29%28x%2By%29)
F.O.I.L. the equation (first, outer, inner, last)
![(x+y)(x+y) = (x*x) + (x*y) + (x*y) + (y*y)](https://tex.z-dn.net/?f=%28x%2By%29%28x%2By%29%20%3D%20%28x%2Ax%29%20%2B%20%28x%2Ay%29%20%2B%20%28x%2Ay%29%20%2B%20%28y%2Ay%29)
![(x*x) + (x*y) + (x*y) + (y*y) = x^2 + xy +xy+y^2 = x^2 +2xy+y^2](https://tex.z-dn.net/?f=%28x%2Ax%29%20%2B%20%28x%2Ay%29%20%2B%20%28x%2Ay%29%20%2B%20%28y%2Ay%29%20%3D%20x%5E2%20%2B%20xy%20%2Bxy%2By%5E2%20%3D%20x%5E2%20%2B2xy%2By%5E2)
we are given
A ball rolling down a hill was displaced 19.6 m
so,
![h=19.6m](https://tex.z-dn.net/?f=h%3D19.6m)
the final velocity was 5.00m/s
so, ![v=5m/s](https://tex.z-dn.net/?f=v%3D5m%2Fs)
Since, a ball rolling down a hill was displaced
so, we get
![u=0m/s](https://tex.z-dn.net/?f=u%3D0m%2Fs)
we can use kinematic equation formula
![v^2-u^2=2ah](https://tex.z-dn.net/?f=v%5E2-u%5E2%3D2ah)
Here ,
v is final velocity
u is initial velocity
a is acceleration
h is height from which ball is dropped
now, we can plug our values
![5^2-0^2=2a(19.6)](https://tex.z-dn.net/?f=5%5E2-0%5E2%3D2a%2819.6%29)
![2a\left(19.6\right)=5^2](https://tex.z-dn.net/?f=2a%5Cleft%2819.6%5Cright%29%3D5%5E2)
![2a\left(19.6\right)=25](https://tex.z-dn.net/?f=2a%5Cleft%2819.6%5Cright%29%3D25)
................Answer