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3 years ago

Many flags are stored in a wooden triangular shaped box. How much wood is needed to go around the outside of the frame?

Mathematics

1 answer:

Lapatulllka [165]3 years ago

8 0

i uploaded a vid on this here

https://www.you tube.com/watch?v=dQw4w9WgXcQ

its actually c tho..

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3 years ago

ABC and EDC are straight lines. EA is parallel to DB. EC = 8.1 cm. DC = 5.4 cm. DB = 2.6 cm. (a) Work out the length of AE. cm (

harkovskaia [24]

By applying the knowledge of similar triangles, the lengths of AE and AB are:

a. $\mathbf{AE = 3.9 $ cm}\\\\$

b. $\mathbf{AB = 2.05 $ cm} \\\\$

See the image in the attachment for the referred diagram.

The two triangles, triangle AEC and triangle BDC are similar triangles.
Therefore, the ratio of the corresponding sides of triangles AEC and BDC will be the same.

This implies that:

AC/BC = EC/DC = AE/DB

Given:

$EC = 8.1 $ cm\\\\DC = 5.4 $ cm\\\\DB = 2.6 cm\\\\AC = 6.15 $ cm$

a. Find the length of AE:

EC/DC = AE/DB

Plug in the values

$\frac{8.1}{5.4} = \frac{AE}{2.6}$

Cross multiply

$5.4 \times AE = 8.1 \times 2.6\\\\5.4 \times AE = 21.06$

Divide both sides by 5.4

$AE = \frac{21.06}{5.4} = 3.9 $ cm$

b. Find the length of AB:

$AB = AC - BC$

AC = 6.15 cm

To find BC, use AC/BC = EC/DC.

Plug in the values

$\frac{6.15}{BC} = \frac{8.1}{5.4}$

Cross multiply

$BC \times 8.1 = 6.15 \times 5.4\\\\BC = \frac{6.15 \times 5.4}{8.1} \\\\BC = 4.1$

Thus:

$AB = AC - BC$

Substitute

$AB = 6.15 - 4.1\\\\AB = 2.05 $ cm$

Therefore, by applying the knowledge of similar triangles, the lengths of AE and AB are:

a. $\mathbf{AE = 3.9 $ cm}\\\\$

b. $\mathbf{AB = 2.05 $ cm} \\\\$

Learn more here:

brainly.com/question/14327552

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3 years ago

<img src="https://tex.z-dn.net/?f=%5Csqrt%7B4x%2B1%7D-5%3D0%5C%5C%5C%5C%5C%5C%5C%5C%5Csqrt%7B5x-1%7D%2B3%3Dx%5C%5C" id="TexFormu

adoni [48]

Answer:

what topic is this please

8 0

3 years ago

Many flags are stored in a wooden triangular shaped box. How much wood is needed to go around the outside of the frame? ​

Many flags are stored in a wooden triangular shaped box. How much wood is needed to go around the outside of the frame?