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oksano4ka [1.4K]
3 years ago
5

PLEASE HELP EXPLAIN!!!!!

Mathematics
1 answer:
Nookie1986 [14]3 years ago
4 0
I think( so correct me if i'm wrong).....Using the distance formula... D=Rate x Time, you alter it so that it equals time, since you want to find the number of weeks.
Time = Distance/ rate
SInce you start off at 2 and end up with 5, the total distance is 3 (I subtracted 5-2). And rate is already 12% (this is the iffy part, I'm not sure if you change the 12%  in anyway.... but lets move on)

SO Time= 3miles/ 12% which is 1/4 of a week, or possibly.....

Time = 3 miles/ 0.12 which would equal 25 weeks.....
Do they give you these answers?
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Helga [31]
Yes, it is bigger than 0
3 0
3 years ago
Line b passes through points (9, 1) and (1, 6). Line c passes through points (10, 7) and (2, 12). Are line b and line c parallel
andre [41]
<h2>Answer:  Lines b & c are parallel.⇄</h2>

Step-by-step explanation:

  • When lines are perpendicular, the product of their slope is -1 (the slopes are negative reciprocal).
  • When lines are parallel, they have the same slope.

Slope = ( y₂ - y₁) / (x₂ - x₁)

Slope of Line b = ( 6 - 1 ) ÷ ( 1 - 9 )

                         =  5  ÷  (- 8)

                         =   - ⁵/₈

Slope of Line c =  ( 12 - 7 )  ÷  ( 2 - 10 )

                         =  - ⁵/₈

⇒ Line b ║ Line c

8 0
3 years ago
Help please asap i will give brainlist
7nadin3 [17]
28°

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180°-140°= 40°
180°-68°= 112°
180°-112°-40°= 28°
3 0
3 years ago
Jaleel wrote a book. He wants to print some copies for
kotykmax [81]
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3 years ago
Convert,the complex number into polar form: 4+4i
kow [346]
Z = a + bi
z = 4 + 4i

r² = a² + b²
r² = (4)² + (4)²
r² = 16 + 16
r² = 32
 r = 4√(2)
 r = 4(1.414)
 r = 5.656

cos\theta = \frac{a}{r}
cos\theta = \frac{4}{4\sqrt{2}}
cos\theta = \frac{4}{4\sqrt{2}} * \frac{\sqrt{2}}{\sqrt{2}}
cos\theta = \frac{4\sqrt{2}}{4\sqrt{4}}
cos\theta = \frac{4\sqrt{2}}{4(2)}
cos\theta = \frac{4\sqrt{2}}{8}
cos\theta = \frac{\sqrt{2}}{2}
2(cos\theta) = 2(\frac{\sqrt{2}}{2})
2cos\theta = \sqrt{2}
2cos\theta = 1.414

sin\theta = \frac{b}{r}
sin\theta = \frac{4}{4\sqrt{2}}
sin\theta = \frac{4}{4\sqrt{2}} * \frac{\sqrt{2}}{\sqrt{2}}
sin\theta = \frac{4\sqrt{2}}{4\sqrt{4}}
sin\theta = \frac{4\sqrt{2}}{4(2)}
sin\theta = \frac{4\sqrt{2}}{8}
sin\theta = \frac{\sqrt{2}}{2}
2(sin\theta) = 2(\frac{\sqrt{2}}{2})
2sin\theta = \sqrt{2}
2sin\theta = 1.414

z = a + bi
z = rcosθ + (rsinθ)i
z = r(cosθ + i sinθ)

z = 4 + 4i
z = 5.656cosθ + (5.656sinθ)i
z = 5.656(cosθ + i sinθ)
z = 5.656(cos45 + i sin45)

\theta = tan^{-1}\frac{b}{a}
\theta = tan^{-1}\frac{4}{4}
\theta = tan^{-1}(1)
\theta = 45

The polar form of 4 + 4i is approximately equal to 5.656(cos45 + i sin45).
5 0
3 years ago
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