All categories

3 years ago

Which equation matches the function described in Table

Mathematics

1 answer:

Crank3 years ago

3 0

Answer:

The answer is A

Step-by-step explanation:

A because it's simply adding by 4 on the right-hand side.

You might be interested in

Plz answer will give brainliest

Alex73 [517]

Given quadratic equation

$x^2+6x+6=0$
Using the usual conventions,
a=1, b=6, c=6
Apply the quadratic formula,
$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$
substitute a,b & c with numerical values,
$x=\frac{-6\pm\sqrt{6^2-4(1)(6)}}{2(1)}$
simplify:
$x=\frac{-6\pm\sqrt{12}}{2}$

7 0

3 years ago

If x+1/x= 3, then prove that m^5+1/m^5= 123

alina1380 [7]

9514 1404 393

Explanation:

We can start with the relations ...

$\displaystyle\left(x+\frac{1}{x}\right)^3=\left(x^3+\frac{1}{x^3}\right)+3\left(x+\frac{1}{x}\right)\\\\\left(x+\frac{1}{x}\right)^5=\left(x^5+\frac{1}{x^5}\right)+5\left(x^3+\frac{1}{x^3}\right)+10\left(x+\frac{1}{x}\right)\\\\\textsf{From these, we can derive ...}\\\\x^5+\frac{1}{x^5}=\left(x+\frac{1}{x}\right)^5-5\left(\left(x+\frac{1}{x}\right)^3-3\left(x+\frac{1}{x}\right)\right)-10\left(x+\frac{1}{x}\right)$

$\displaystyle x^5+\frac{1}{x^5}=\left(x+\frac{1}{x}\right)^5-5\left(x+\frac{1}{x}\right)^3+5\left(x+\frac{1}{x}\right)\right)\\\\x^5+\frac{1}{x^5}=3^5 -5(3^3)+5(3)\\\\=((3^2-5)3^2+5)\cdot3=(4\cdot9+5)\cdot3=(41)(3)\\\\=\boxed{123}$

7 0

3 years ago

What is the distance between the points plotted below? If necessary, round your answer to two decimal places.

34kurt

(-1,1) (6,9)
distance = root (x1-x2)²+(y1-y2)²
so root (-1-6)²+(1-9)²= root 113 or 10.6 ≈11
the answer is B. 11.18 units

8 0

3 years ago

Read 2 more answers

What is the answer to y=x+2

trasher [3.6K]

Answer:

Slope of 1 with a y-intercept of 2

Step-by-step explanation:

4 0

3 years ago

one bag of grapefruit weighs4 pounds. How many pounds of grapefruit are in bags? O 82 pounds Ol pounds o 11 unds O 182 pounds

Citrus2011 [14]

Answer:

Step-by-step explanation:

The bag weighed 31116 pounds. Explanation: First, we need to get all three of our fractions under a common denominator. To do this, let's first change

8 0

3 years ago