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sveticcg [70]
3 years ago
9

What is the value of the expression k – 14 when k = –17? a.–31 b.–3 c.3 d.31

Mathematics
1 answer:
NeX [460]3 years ago
8 0
(-17) - 14 = (-17) + (-14) = -31
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Step-by-step explanation:

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What is the total resistance of a parallel circuit that has two loads? Load one has a resistance of 10 ohms. Load two has a resi
Romashka-Z-Leto [24]

Answer:

The total resistance is 7.0588\Omega

Step-by-step explanation:

Attached please find the circuit diagram. The circuit is composed by a voltage source and two resistors connected in parallel: R_1=10\Omega and R_2=24\Omega.

First step: find the total current

For finding the current that the voltage source can provide, you must find the current consumed by each load and then add both. To do that, take first into account that the voltage is the same for both resistors (R_1 and R_2).

  • I_{R_1}=\frac{V_S}{R_1}
  • I_{R_2}=\frac{V_S}{R_2}

The total current is:

I_{TOTAL}=I_{R_1}+I_{R_2}=\frac{V_S}{R_1}+\frac{V_S}{R_2}=\frac{R_2\cdot V_S+R_1\cdot V_S}{R_1\cdot R_2}

I_{TOTAL}=V_S\cdot \frac{R_1+R_2}{R_1\cdot R_2}

Now, the total resistance (R_{TOTAL}) would be the voltage divided by the total current:

R_{TOTAL}=\frac{V_S}{I_{TOTAL}}

If you replace I_{TOTAL} by the expression obtained previously, the total resistance would be:

R_{TOTAL}=\frac{V_S}{V_S\cdot \frac{R_1+R_2}{R_1\cdot R_2}}

After simplifying the terms you should get:

R_{TOTAL}=\frac{R_1\cdot R_2}{R_1 + R_2}}

Now, you must replace the values of the resistors:

R_{TOTAL}=\frac{(10\Omega )\cdot (24\Omega)}{10\Omega + 24\Omega}}=\frac{120}{17}\Omega=7.0588\Omega

Thus, the total resistance is 7.0588\Omega

3 0
3 years ago
What is the value of v? 29v 4−23v=5 enter your answer in the box.?
adell [148]
6
iuytgfdsfrgthyjikjuhgf sorry please medal ;p
3 0
3 years ago
The set of possible values of m is (5, 7, 9).
k0ka [10]

Plug in each possible value into the equation.

when m = 5

2k = m + 3

2k = (5) + 3

Simplify

2k = 8

isolate the k, divide 2 from both sides

2k/2 = 8/2

k = 8/2

k = 4

When m = 5, k = 4

-------------------------------------------------------------------------------------------------------------------

2k = m + 3

when m = 7

2k = (7) + 3

2k = 10

2k/2 = 10/2

k = 10/2

k = 5

when m = 7, k = 5

------------------------------------------------------------------------------------------------------------------

2k = m + 3

When m = 9

2k = (9) + 3

2k = 12

2k/2 = 12/2

k = 12/2

k = 6

when m = 9, k = 6

-------------------------------------------------------------------------------------------------------------------

hope this helps

4 0
3 years ago
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