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alexandr402 [8]
3 years ago
6

Hi guys need help?????

Mathematics
1 answer:
Roman55 [17]3 years ago
3 0

Answer:

A. 17

hope this helps have a great day

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Which decimal is equal to four-fifths? 0.6 0.8 0.2 0.3 0.4
DochEvi [55]
4/5 = 80/100

0.8 = 80/100

4/5 = 0.8

hope this helps
4 0
2 years ago
The product of x and y is less than or equal to 4
aleksklad [387]
Xy (less than or equal to sign) 4
4 0
3 years ago
2) Write an integer to best describe<br> the following situation: 6 feet below<br> sea level
Ulleksa [173]

Answer: -6

Step-by-step explanation:

Because its 6 feet below sea level, it should be negative, and since its 6 feet, it would be -6.

8 0
3 years ago
Vonna scored 35 goals at soccer practice. Her ratio of goals to misses was 5:8. How many times did she miss?
Digiron [165]

<u>Answer:</u> She misses 56 times at a soccer practice.

<u>Step-by-step explanation:</u>

Let the goals she misses be 'x'.

According to the question:

5:8::35:x

These two ratios follow direct relationship, so:

\frac{5}{8}=\frac{35}{x}\\\\5x=35\times 8\\\\x=\frac{280}{5}\\\\x=56

Hence, Vonna misses 56 times at a soccer practice.

5 0
3 years ago
in a final exam you have four multliple choice questions left to do. each questions has five suggested answers and only one of t
kompoz [17]

Answer:

The probability that you get zero questions correct is 0.4096

The probability that you get one questions correct is 0.4096

The probability that you get three questions correct is 0.0256

Step-by-step explanation:

These probability can be describe with a Binomial Distribution. These distribution can be used when we have n identical and independent situations in which there is a probability p or probability of success and a probability q or probability of fail. Additionally q is equal to 1 - p. The probability of x for a situation in which we can apply binomial distribution is:

P( x,n,p) = n Cx * p^{x } * q^ {n-x}

Where x is the variable that says the number of success in the n situations

And nCx is calculate as:

nC x = \frac{ n!}{ x! (n-x)! }

From the question we can identify that:

  • n is equal to 4 multiple choice question
  • p is 1/5 or 0.2, the probability of get one question correct
  • q is 4/5 or 0.8, the probability of get one question incorrect

Then the probability of get zero questions correct of 4 questions is:

P( 0, 4, 0.2) = 4 C0 * p^{0 } * q^ {4-0}= 0.4096

The probability of get one question correct of 4 questions is:

P( 1, 4, 0.2) = 4 C1 * p^{1 } * q^ {4-1}= 0.4096

The probability of get three questions correct of 4 questions is:

P( 3, 4, 0.2) = 4 C3 * p^{3 } * q^ {4-3}= 0.0256

8 0
3 years ago
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