Solve: 63z2+61z=−6. Multiple answers

THIS PROBLEM IS WORTH 50 POINTS!!! WHAT IS 2+2×9÷3+10-45+21=

inn [45]

Hello,

Shall we begin?

= 2 + 2×9÷3+10-45+21
= 2 + 18 : 3 + 10 - 45 + 21
= 2 + 6 + 10 - 45 + 21
= - 6

Answers: - 6

8 0

3 years ago

What is (-4)x(-6)= that’s it

igor_vitrenko [27]

Answer:

24

Step-by-step explanation:

the negatives cancel each other out

8 0

3 years ago

Read 2 more answers

An open top rectangular box with a square bottom has a volume of 120 cubic meters. Its bottom and sides are made from two differ

denpristay [2]

Answer:

The dimensions that minimizes the cost are a= 6.604 (lenght of a side) and h=2.752 (height)

Step-by-step explanation:

Let's define some notation first:

h = represent the height of the box

a= length of a side on the bottom

We need to remember that we have on this case an open box, so then we don't have a top part.

Let's begin with the formula for the volume of the box, we have a total volume given of $120m^3$ , and we know that the volume for a box is the product of the area and the height like this:

$120 m^3 = a^2 h$ (1)

From equation (1) we cna solve for the height and we got:

$h=\frac{120}{a^2}$ (2)

Now let's move to th surface area formula. The top bottom area is $a^2$ and the surface area for the four lateral sides is 4ah. Since we know that the cost for the bottom material is 10 $ per each square meter and for the sides is 12$ per square meter we can create a function cost like this:

$Cost= Cost of bottom+ Cost of sides$

$Cost = 10a^2 + (12)(4ah) = 10a^2 + 48ah$ (3)

Now we can substitute into equation (3) the equation (2) like this:

$Cost = 10a^2 + (12)(4ah) = 10a^2 + 48a\frac{120}{a^2}=10a^2 +\frac{5760}{a}$ (4)

Now in order to find the minimum cost, we can take the first derivate for the expression (4) like this

$\frac{d}{da} Cost = 20a -\frac{5760}{a^2}$

We can set this equal to 0 and solve for a and we got:

$\frac{5760}{a^2}= 20a$

$\frac{5760}{20}=a^3$

$a=6.604$

And since we have a we can find h using the expression (2) like this:

$h=\frac{120}{a^2}=\frac{120}{6.604^2}=2.752$

So then the dimensions that minimizes the cost are a= 6.604 (lenght of a side) and h=2.752 (height)

6 0

3 years ago

??????????????????????

irga5000 [103]

Answer:

A = 254.34

Step-by-step explanation:

Area of a circle formula:

A = πr²

r = d/2 = 9

A = 3.14(9²)

A = 3.14(81)

A = 254.34

4 0

3 years ago

Read 2 more answers

The vertices of triangle ABC are A(1,1), B(0,2), and C(3,-2). Find the coordinates of the circumcenter. ...?

maria [59]

To find the circumcenter, solve any two bisector equations and find out the intersection points. The given are A(1,1), B(0,2), and C(3,-2).

Midpoint of AB = (1/2, 3/2) - You can get the midpoint by getting the average of x-coordinates and y-coordinates.

Slope of AB = -1
Slope of perpendicular bisector = 1
Equation of AB with slope 1 and the coordinates (1/2, 3/2) is
y - (3/2) = (1)(x - 1/2)
y = x+1

Do the same for AC
Midpoint of AC = (2, -1/2)
Slope of AC = -3/2
Slope of perpendicular bisector = 2/3
Equation of AC with slope 2/3 and the coordinates (2, -1/2) is
y - (-1/2) = (2/3)(x - 2)
y = -11/6 + 2x/3

So the perpendicular bisectors of AB and BC meet
y = x+1
y = -11/6 + 2x/3

To solve for x,
(-11/6 + 2x/3) = (x+1)
x= -17/2

Now get y by substituting
y = (-17/2) + 1
y = -15/2

The circumcenter is (-17/2, -15/2)

Thank you for posting your question. I hope that this answer helped you. Let me know if you need more help.

8 0

3 years ago