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Roman55 [17]
3 years ago
6

Multiple. 7i (4-2i)

Mathematics
1 answer:
Eddi Din [679]3 years ago
7 0

Answer:

14+28i

Step-by-step explanation:

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Please help fast......
Tom [10]

3)

\begin{array}{c|c}\underline{Statement}&\underline{Reason}\\ 1.AY=BX&\text{1. Given}\\ 2.AB \cong AB&\text{2. Reflexive Property}\\ 3. AD || BC&\text{3. Property of a square}\\ 4. \angle ABE \cong \angle AXB&\text{4. Alternate Interior Angles}\\ 5. \angle BAY \cong \angle BYA&\text{5. Alternate Interior Angles}\\6. \triangle BAX \cong \triangle ABY&\text{6. Angle-Side-Angle Theorem}\\ 7. AX \cong BY&\text{7. CPCTC}\\\end{array}

*************************************************************************************

6)

\begin{array}{c|c}\underline{Statement}&\underline{Reason}\\1. AB=CF&\text{1. Given}\\2.AB+BF=A'F&\text{2. Segment Addition Postulate}\\3.CF+BF=A'F&\text{3. Substitution Property}\\4.CF+BF+BC&\text{4. Segment Addition Postulate}\\5.A'F=BC&\text{5. Transitive Property}\\6. \angle AFE = \angle DBC&\text{6. Given}\\7. EF = BD&\text{7. Given}\\8. \triangle AFE \cong \triangle CBD&\text{8. Side-Angle-Side Theorem}\\\end{array}

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7)

\begin{array}{c|c}\underline{Statement}&\underline{Reason}\\\text{1.AC bisects }\angle BAD&\text{1. Given}\\2. \angle BAC \cong \angle DAC&\text{2. Property of angle bisector}\\3.AC = AC&\text{3. Reflexive Property}&4. \angle ACB \cong \angle ACD&\text{4. Property of angle bisector}\\5. \triangle ABC \cong \triangle ADC&\text{5. Angle-Side-Angle Theorem}\\6.BC=CD&\text{6. CPCTC}\\\end{array}

5 0
4 years ago
The elevations, in feet, of three cities are marked on the number line shown below.
Dmitriy789 [7]
I think the answer it C
7 0
3 years ago
Read 2 more answers
What is the perimeter, in units, of polygon UVWXYZ? Enter your answer in the box.
nikitadnepr [17]

Given:

Consider the below figure attached with this question.

To find:

The perimeter of the polygon UVWXYZ.

Solution:

All sides and vertical and horizontal. So, we can easily find the side lengths of the given polygon by counting the boxes between two points.

From the figure it is clear that,

UV = 9 units

VW = 2 units

WX = 3 units

XY = 3 units

YZ = 6 units

ZU = 5 units

Now, perimeter is the sum of all the sides.

Perimeter=UV+VW+WX+XY+YZ+ZU

Perimeter=9+2+3+3+6+5

Perimeter=28

Therefore, the perimeter of UVWXYZ is 28 units.

6 0
3 years ago
Which of the following in an identity?
sammy [17]
By "which is an identity" they just mean "which trigonometric equation is true?"

What you have to do is take one of these and sort it out to an identity you know is true, or...

*FYI: You can always test identites like this:
Use the short angle of a 3-4-5 triangle, which would have these trig ratios:
sinx = 3/5    cscx = 5/3
cosx = 4/5   secx = 5/4
tanx = 4/3    cotx = 3/4
Then just plug them in and see if it works. If it doesn't, it can't be an identity!

Let's start with c, just because it seems obvious.
The Pythagorean identity states that sin²x + cos²x = 1, so this same statement with a minus is obviously not true.

Next would be d. csc²x + cot²x = 1 is not true because of a similar Pythagorean identity 1 + cot²x = csc²x. (if you need help remembering these identites, do yourslef a favor and search up the Magic Hexagon.)

Next is b. Here we have (cscx + cotx)² = 1. Let's take the square root of each side...cscx + cotx = 1. Now you should be able to see why this can't work as a Pythagorean Identity. There's always that test we can do for verification...5/3 + 3/4 ≠ 1, nor is (5/3 +  3/4)².

By process of elimination, a must be true. You can test w/ our example ratios:
sin²xsec²x+1 = tan²xcsc²x
(3/5)²(5/4)²+1 = (4/5)²(5/3)²
(9/25)(25/16)+1 = (16/25)(25/9)
(225/400)+1 = (400/225)
(9/16)+1 = (16/9)
(81/144)+1 = (256/144)
(81/144)+(144/144) = (256/144)
(256/144) = (256/144)
5 0
3 years ago
Solve this equation<br> 3x - 5 = -26​
Dmitry_Shevchenko [17]

3x - 5 = -26​

<u>step 1:</u>

subtract +5 on each side because you have to do the inverse operation

<u>step 2:</u>

3x= -21

<u>step 3:</u>

now divide 3 on each side

the answer is -7

<u />

Hope this helped!

<u />

<em>TheOneAndOnlyLara~</em>

5 0
2 years ago
Read 2 more answers
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