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koban [17]
3 years ago
12

The theory of population growth based on geometric and arithmetic progressions is the

Mathematics
1 answer:
ziro4ka [17]3 years ago
6 0
<span>The theory of population growth based on geometric and arithmetic progressions is the Malthusian theory.</span>  
<span>
To add, <span>in his 1798 work, An Essay on the Principle of </span>Population<span>, </span>Malthus<span> <span>examined the relationship between </span></span>population<span> growth and resources and developed the </span>Malthusian theory of population<span> <span>growth.<span> </span></span></span></span>
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Equivalent expression 5.4 x 10 to the 5th power - 1.4 x 10 to the 4th
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<h2>5.4 × 10⁵ - 1.4 × 10⁴ = 540,000 - 14,000 = 526.000</h2><h2 /><h2 />
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If Mateo converts his anxiety score into a z-score, he can both indicate how many standard deviation units his score is from the
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Answer:

The answer is "Option a"

Step-by-step explanation:

In the given scenario, the z-score value is used as the score which is used to shows that how many standard deviation units in this score were uses as the from mean  and whenever this score is above or below by the mean, therefore the given statement is true.

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The manufacturer of a certain type of new cell phone battery claims that the average life span of the batteries is 500 charges;
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When the author visited Dublin, Ireland (home of Guinness Brewery employee William Gosset, who first developed the t distributio
disa [49]

Answer:

The  Decision Rule

Fail to reject the null hypothesis

The conclusion

 There is no sufficient evidence to support the claim that the mean age of the cars is greater than that of taxi

Step-by-step explanation:

From the question we are told that

   The data is  

      Car Ages 4 0 8 11 14 3 4 4 3 5 8 3 3 7 4 6 6 1 8 2 15 11 4 1 6 1 8

     Taxi Ages 8 8 0 3 8 4 3 3 6 11 7 7 6 9 5 10 8 4 3 4

      The  level of significance \alpha = 0.05

 Generally the null hypothesis  is  H_o  :  \mu_1 - \mu_2  = 0

                  the alternative hypothesis is   H_a  :  \mu_1 - \mu_2 >  0

Generally the sample mean for the age of  cars is mathematically represented as

        \= x_1 = \frac{\sum x_i }{n}

=>     \= x_1 = \frac{4+ 0+ 8 +11 + \cdots + 8&#10;}{27}

=>     \= x_1 = 5.56

Generally the standard deviation of age of  cars

     \sigma _1  = \sqrt{\frac{\sum (x_i - \= x)^2}{n_1} }

=>  \sigma _1  = \sqrt{\frac{(4 - 5.56)^2 + (0 - 5.56)^2+ (8 - 5.56)^2 + \cdots + 8}{ 27} }

=>  \sigma _1  =  3.88

Generally the sample mean for the age of taxi is mathematically represented as

        \= x_2 = \frac{\sum x_i }{n}

=>     \= x_2 = \frac{8 +8 +0  + \cdots + 4&#10;}{20}

=>     \= x_2 = 5.85

Generally the standard deviation of age of  taxi

\sigma _2  = \sqrt{\frac{\sum (x_i - \= x)^2}{n_1} }

=>  \sigma _2  = \sqrt{\frac{(8 - 5.85)^2 + (8 - 5.85)^2+ (0 - 5.85)^2 + \cdots + 8}{ 20} }

=>  \sigma _2  = 2.83

Generally the test statistics is mathematically represented as

   t = \frac{(\= x_ 1 - \= x_2 ) - 0}{\sqrt{\frac{\sigma^2_1}{n_1}  + \frac{\sigma^2_2}{n_2} }  }

=> t = \frac{(5.56 - 5.85 ) - 0}{\sqrt{\frac{(3.88)^2}{27}  + \frac{(2.83)}{20} }}  

=> t = -0.30  

Generally the degree of freedom is mathematically  represented as

   df =  n_1 + n_2 -2

    df =  27 +  20 -2

    df =  45

From the t distribution table  the P(t >  t ) at the obtained degree of freedom = 45 is  

   P(t >  -0.30 ) = 0.61722067

So  the  p-value  is

    p-value  =  P(t >  T) =  0.61722067

From the obtained values we see that the  p-value  >  \alpha hence we fail to reject the null hypothesis

Hence the there is no sufficient evidence to support the claim that the mean age of the cars is greater than that of taxi

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3 years ago
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