I think it would be commutative or associative because there is anything to distribute so it is NOT distributive
We can model this situation.
Raina received a total of 83 calls
First evening she received 7 more than the third so let x = third and since we know she received 7 more we know to add 7 to the third so (x + 7)
Second evening she received 2 times as many as the third so 2 time third, which x is the third so (2 times x) or we could say 2x
Third evening = x
So now lets solve for x and then we can find how many she received each evening.
Our Model: (x + 7) + 2x + x = 83
(x + 7) + 2x + x = 83
x + 7 + 2x + x = 83
x + 2x + x + 7 = 83
4x + 7 = 83
4x + 7 - 7 = 83 -7
4x = 76
4x / 4 = 76 / 4
x = 19
First evening:
19 + 7 = 26 calls
Second evening
2 times 19 = 38
Third evening
19
Check our answer:
26 + 38 + 19 = 83
2x + 5(–4x + 10) - (x + 4).
-4+10=14
x+4=5-9
2x+5=7x
7+9=18
18-14=4
4 is your answer
First, isolate y in 7x-y=29 because 1 is y's coefficient.
7x-y=29
-y=29-7x
y=7x-29
Now, substitute 7x-29 for y in 7x+8y=20.
7x+8y=20
7x+8(7x-29)=20
7x+56x-232=20
Add all coefficients.
63x-232=20
Isolate x by adding 232 to both sides.
63x-232=20
63x=252
x=4
Now, substitute 4 for x in your first equation.
y=7x-29
y=7(4)-29
y=28-29
y=-1
Your answer would be (4,-1).
Any questions you may have, please contact me or comment.
