Total = Principal * (1 + rate)^years
Total = 50,000 * (1.034)^10
<span><span><span>Total = 50,000 * 1.3970288911
</span>
</span>
</span>
Total =
<span>
<span>
<span>
69,851.44</span></span></span>
The graph of P = 35 - 1/4Q is a straight line passing through points (0, 35) and (140, 0)
Answer:
x= 20 i think sorry if it's wrong⊙﹏⊙
Answer:
(1) ΔMAN ≅ ΔBOY
(2) ΔMAT ≅ ΔRUG
(3) ΔEBN ≅ ΔUHR
(4) ΔTOP ≅ ΔLID
(5) ΔCAT ≅ ΔDOG
(6) ΔITP ≅ ΔLOH
Step-by-step explanation:
The following combinations of the congruent triangle facts will be sufficient to prove triangles congruent.
The combinations are:
(1) SSS (side-side-side) : If three sides of a triangle are congruent to three sides of another triangle then the triangles are congruent.
(2) SAS (side-angle-side) : If two sides and included angle of a triangle are congruent to another triangle then the triangles are congruent.
(3) ASA (angle-side-angle) : If two angles and included side of a triangle are congruent to another triangle then the triangles are congruent.
(4) RHS (right angle-hypotenuse-side) : If the hypotenuse and leg of one right triangle are congruent to the corresponding parts of another right triangle, the right triangles are congruent.
Part (1):
As we are given two triangles.
Side AM = Side OB
Side MN = Side BY
Side AN = Side OY
That means,
ΔMAN ≅ ΔBOY
Part (2):
As we are given two triangles.
Side MA = Side RU
Side MT = Side RG
Side AT = Side UG
That means,
ΔMAT ≅ ΔRUG
Part (3):
As we are given two triangles.
Side EB = Side UH
Side BN = Side HR
Side NE = Side RU
That means,
ΔEBN ≅ ΔUHR
Part (4):
As we are given two triangles.
Side OT = Side IL
Side OP = Side ID
Side PT = Side DL
That means,
ΔTOP ≅ ΔLID
Part (5):
As we are given two triangles.
Side AC = Side OD
Side AT = Side OG
Side TC = Side GD
That means,
ΔCAT ≅ ΔDOG
Part (6):
As we are given two triangles.
Side TP = Side OH
Side IT = Side LO
Side IP = Side LH
That means,
ΔITP ≅ ΔLOH
<span>Each die has 6 faces, and the odds of a 6 or 1 showing up are 1 in 6.
So, there are several possible victory conditions:
1 of the 4 dice shows a 1, and none show 6.
2 of the dice show one and one or none show 6.
3 of the dice show one, and 2 or less show 6.
All 4 dice show 6.
There are 1296 possible combinations of dice that could be rolled.
So, the probabilities are as follows.
4 in 81 1 of the 4 dice shows a 1, and none show 6.
1 in 81 2 of the dice show one and one or none show 6.
5 in 1296 3 of the dice show one, and the 4 th die result doesn't matter, as long as it isn't 1.
1 in 1269 - All 4 dice show 6.
So,there is a 43 in 648 chance of this occurring.</span>