The diagonals of a rectangle have length 12 and intersect in a 40 degree angle. Find the length and width rounded to the nearest
tenth.
1 answer:
Answer:
Length is 7.7 and width is 9.2
Step-by-step explanation:
The length and width of the rectangle will be the y and x coordinate of the diagonal line at angle of 40 degrees
Length L = dsin theta
Width W = d coos theta
d is the length of the diagonal
Given
d = 12
theta = 40°
Substitute
Length = 12sin40°
Length = 12(0.6428)
Length = 7.7135
Length ≈ 7.7
Width = 12cos 40
Width = 12(0.7660)
Width = 9.192
Width = 9.2
Hence the length is 7.7 and width is 9.2
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Step-by-step explanation:
Done. You're welcome
