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Lena [83]
3 years ago
8

When creating vases for the craft fair, Thomas used the proportion 3 pounds of clay is to 8 vases as 9 pounds of clay is to 24 v

ases. Which proportion can be used to represent the situation? StartFraction 3 over 8 EndFraction = StartFraction 24 over 9 EndFraction StartFraction 3 over 8 EndFraction = StartFraction 9 over 24 EndFraction StartFraction 3 over 9 EndFraction = StartFraction 24 over 8 EndFraction StartFraction 9 over 3 EndFraction = StartFraction 8 over 24 EndFraction
Mathematics
2 answers:
Elodia [21]3 years ago
5 0

Answer:

Answer:

4/24

Step-by-step explanation:

Because 1/6 is 4/24 simplified.

To prove this, all you have to do is try simplifying 4/24 yourself. To do that, we are going to use 4 to divide both the numerator and the denominator because 4 is a common factor of 4 and 24.

(To simplify a fraction, you divide both the numerator and denominator by a common factor)

So 4 divided by 4 is 1, and 24 divided by 4 is 6

1/6

99% sure im right ;)

Otrada [13]3 years ago
5 0

Answer: the answer is 3            9

                                     ___    = ___  

                                       8           24

Step-by-step explanation: i just took the test hope it helps:)

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16 - 12 + 60 = 9

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7 0
3 years ago
Read 2 more answers
What is w=138.24/9.6×3.2
RSB [31]
4.5 is the answer.
First you multiply 9.6x3.2 which gives us 30.72 
Then you divide 138.24 by 30.72 which equals 4.5
Hope this helps
5 0
3 years ago
Read 2 more answers
Serena has 3 3/5sq meters of wrapping paper for presents. Her grandmother has 1 1/2sq meters of wrapping paper. How much wrappin
levacccp [35]

Answer:

Total wrapping papers Serena and her grandmother = 51/10

Step-by-step explanation:

Serena's wrapping paper for parents:

  • 3\frac{3}{5}=\frac{18}{5} sq meters

Grandmother's wrapping paper:

  • 1\frac{1}{2}=\frac{3}{2} sq meters

In order to determine the combined wrapping papers for both Serena and grandmother, all we need is to add both.

i.e.

Total papers = Serena's wrapping paper + Grandmother's wrapping paper

                     =\frac{18}{5}+\frac{3}{2}

                     =\frac{36}{10}+\frac{15}{10}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{c}+\frac{b}{c}=\frac{a+b}{c}

                      =\frac{36+15}{10}

                      =\frac{51}{10}

Therefore, total wrapping papers Serena and her grandmother = 51/10

3 0
3 years ago
The cost of a gallon of milk is $.50 more than five times the cost of a gallon of water. If a
Shkiper50 [21]

Answer:

.50

Step-by-step explanation:

4 0
2 years ago
Plz help me solve this question ASAP without using algebra, Thank u‼️
VashaNatasha [74]

Let cost of 1 box of red pen = x

Let cost of 1 box of black pen = y

Gaga bought 5 red box and her sister 4 black box then total cost is given by

5x+4y

Given that total cost was $44

so equation will be 5x+4y=44...(i)

After exchange

Gaga= 4 red box + 1 Black box

Sister = 1 red box + 3 Black box

then cost for Gaga = 4x+1y

cost for sister = 1x+3y

Given that cost for both after exchange is same so we get

4x+1y = 1x+3y

or 4x-1x = 3y-1y

or 3x = 2y

or 3x/2=y ...(ii)

plug (ii) into (i)

5x+4y=44

5x+4(3x/2)=44

5x+12x/2=44

5x+6x=44

11x=44

x=4

Now plug value of x into (ii)

y=3x/2=3*4/2=12/2=6

Hence cost of 1 box of red pen = $4

And cost of 1 box of black pen = $6

---

If you want to get solution without solving both equations then just graph both equations and find the intersection point.

You will see that graph intersect at (4,6) which gives x=4, y=6

6 0
3 years ago
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