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Lena [83]
3 years ago
8

When creating vases for the craft fair, Thomas used the proportion 3 pounds of clay is to 8 vases as 9 pounds of clay is to 24 v

ases. Which proportion can be used to represent the situation? StartFraction 3 over 8 EndFraction = StartFraction 24 over 9 EndFraction StartFraction 3 over 8 EndFraction = StartFraction 9 over 24 EndFraction StartFraction 3 over 9 EndFraction = StartFraction 24 over 8 EndFraction StartFraction 9 over 3 EndFraction = StartFraction 8 over 24 EndFraction
Mathematics
2 answers:
Elodia [21]3 years ago
5 0

Answer:

Answer:

4/24

Step-by-step explanation:

Because 1/6 is 4/24 simplified.

To prove this, all you have to do is try simplifying 4/24 yourself. To do that, we are going to use 4 to divide both the numerator and the denominator because 4 is a common factor of 4 and 24.

(To simplify a fraction, you divide both the numerator and denominator by a common factor)

So 4 divided by 4 is 1, and 24 divided by 4 is 6

1/6

99% sure im right ;)

Otrada [13]3 years ago
5 0

Answer: the answer is 3            9

                                     ___    = ___  

                                       8           24

Step-by-step explanation: i just took the test hope it helps:)

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∠EFG and ∠GFH are a linear​ pair, m∠EFG=3n+19, and m∠GFH=55+33 What are m∠EFG and m∠​GFH?
romanna [79]
A linear pair is a pair of angles that form a straight line and are therefore, equal to 180 degrees

3n + 19 + 55 + 33 = 180
3n + 107 = 180
3n = 180 - 107
3n = 73
n = 73/3 


so < EFG = 3n + 19 = 3(73/3) + 19 = 73 + 19 = 92
and < GFH = 55 + 33 = 88
5 0
3 years ago
What is the ratio of 267?
Dmitry [639]
The answer is 133.5 I got this by dividing 267 by 2
5 0
2 years ago
6/30=3/15 true or false
Dennis_Churaev [7]

Answer: True

Step-by-step explanation: This is because they are equivalent fractions

Hope this helps and have a nice day

4 0
2 years ago
Read 2 more answers
Which function is an odd function?
Mrac [35]

Answer:

Algebraically, f is even if and only if f(-x) = f(x) for all x in the domain of f. A function f is odd if the graph of f is symmetric with respect to the origin. Algebraically, f is odd if and only if f(-x) = -f(x) for all x in the domain of f.

Step-by-step explanation:

7 0
3 years ago
The accompanying data came from a study of collusion in bidding within the construction industry. No. Bidders No. Contracts 2 6
viktelen [127]

Answer:

a)

The proportion of contracts involved at most five bidders is 0.667.

The proportion of contracts involved at least five bidders is 0.51.

b)

The  proportion of contracts involved  between five and 10 inclusive bidders is 0.5.

The  proportion of contracts involved  strictly between five and 10 bidders is 0.304.

Step-by-step explanation:

No. bidders    No. contracts     Relative frequency of contracts

2                         6                       6/102=0.0588

3                         20                     20/102=0.1961

4                         24                     24/102=0.2353

5                         18                       18/102=0.1765

6                         13                        13/102=0.1275

7                          7                          7/102=0.0686

8                          5                          5/102=0.049

9                          6                          6/102=0.0588

10                         2                           2/102=0.0196

11                          1                            1/102=0.0098

Total                  102

a)

We have to find proportion of contracts involved at most five bidders.

Proportion of at most 5= Relative frequency 2+ Relative frequency 3+ Relative frequency 4+ Relative frequency 5

Proportion of at most 5=0.0588+ 0.1961+0.2353+0.1765

Proportion of at most 5=0.6667

The proportion of contracts involved at most five bidders is 0.667.

proportion of at least five bidders= proportion≥5= 1- proportion less than 5

Proportion less than 5=0.0588+ 0.1961+0.2353=0.4902

proportion of at least five bidders=1-0.4902=0.5098

The proportion of contracts involved at least five bidders is 0.51

b)

We have to find proportion of contracts involved  between five and 10 inclusive bidders.

Proportion of contracts between five and 10 inclusive= Relative frequency 5+ Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9+ Relative frequency 10

Proportion of between five and 10 inclusive=0.1765 +0.1275 +0.0686 +0.049 +0.0588 +0.0196

Proportion of between five and 10 inclusive=0.5

The  proportion of contracts involved  between five and 10 inclusive bidders is 0.5

We have to find proportion of contracts involved  strictly between five and 10 bidders.

Proportion of contracts strictly between five and 10=  Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9

Proportion of strictly between five and 10=0.1275 +0.0686 +0.049 +0.0588

Proportion of strictly between five and 10=0.3039

The  proportion of contracts involved  strictly between five and 10 bidders is 0.304.

8 0
3 years ago
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