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Nata [24]
3 years ago
6

The answer to this question

Mathematics
1 answer:
weqwewe [10]3 years ago
4 0

Answer:

2 miles per hour!

Step-by-step explanation:

It shows that it changes by 2 hours each time! :)

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Solve the fraction <br>1.2 1/2-1 1/4<br>2.1/2+1/4<br>3.1/3+2/5<br>4.1/2-1/3<br>5.1/4-1/3​
DanielleElmas [232]

Answer:

Step-by-step explanation:

1. 1.25

2. 0.75

3.0.73333333333

4. 0.16666666666

5. 0.083333333333333

3 0
3 years ago
Which is not an equation of the line that passes through the points (1, 1) and (5, 5)?
goblinko [34]

Answer:

Step-by-step explanation:

(5-1)/(5-1)= 4/4= 1

y - 1 = x - 1

y = x

y - x = 0

the second equation is not

7 0
3 years ago
A student writes the equation for a line that has a slope of -6 and passes through the point (2, –8). y -(-8) = -6(x - 2) y -(-8
Mice21 [21]
Y - (-8) = -6 (x-2) is correct everything else is not
y + 8 = -6x + 12
y +:8 - 8 = -6x + 12 - 8
y = -6x + 4 is slope intercept form
6 0
3 years ago
Read 2 more answers
A hospital uses cobalt-60 in its radiotherapy treatments for cancer patients. Cobalt-60 has a half-life of 7
NeTakaya

Answer:

We have 197 g of Co-60 after 18 months.

Step-by-step explanation:

We can use the decay equation.

M_{f}=M_{i}e^{-\lambda t}

Where:

  • M(f) and M(i) are the final and initial mass respectively
  • λ is the decay constant (ln(2)/t(1/2))
  • t(1/2) is the half-life of Co
  • t is the time at the final amount of m

M_{f}=228e^{-\frac{ln(2)}{7} 1.5}    

M_{f}=197\: g    

<u>Therefore, we have 197 g of Co-60 after 18 months.</u>

I hope it helps you!

4 0
3 years ago
Can it be solve pq(r²+1)-r(p²+q²)
ivann1987 [24]

Answer:

pqr²+pr-rp²+rq²

Step-by-step explanation:

pq(r²+1)-r(p²+q²)

pqr²+pr-rp²+rq²

3 0
2 years ago
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