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DiKsa [7]
3 years ago
10

What is the standard form of a line?

Mathematics
1 answer:
shutvik [7]3 years ago
4 0
It’s pretty much a special way of writing an equation of a line. it’s another way of writing y=mx+b. it’s Ax+By=C where a b and c are all real numbers and a and b are both not 0.the requirements can depend on what your doing but technically they are real numbers they are most often used as integers and to keep the a positive.also a b and c are usually required to not share common factors
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Please help me and please do what it says to do
zvonat [6]

Answer:

3

Step-by-step explanation:

Reduseduse the number with the greatest common factor 4

7 0
4 years ago
If MN=NQ and MQ=QR=RP, calculate for x​
Akimi4 [234]

Answer:

  • C. 18°

Step-by-step explanation:

  • <em>Refer to attached diagram</em>
<h3>Given </h3>
  • MN = NQ
  • MQ = QR = RP
  • NMR = 3x
  • QMR = x
<h3>To find</h3>
  • Value of x
<h3>Solution</h3>
  • MN = NQ  ⇒ ∠MRN = ∠QMN = 3x+x = 4x
  • MQ = QR ⇒ ∠MRQ = ∠QMR = x

<u>RQP is exterior angle of ΔMQR ⇒ </u>

  • ∠RQP = x + x = 2x

<u>QR = RP ⇒ </u>

  • ∠RPQ = ∠RQP = 2x

<u>∠QRN is exterior angle of ΔQRP ⇒ </u>

  • ∠QRN = 2x + 2x = 4x
  • ∠MRN = ∠QRN - ∠QRM = 4x - x = 3x

<u>∠MRN = ∠NMR = 3x ⇒ </u>

  • NR = MQ

<u>NR = MQ ⇒ </u>

  • ∠NQR = ∠QRN = 4x

<u>We now have a straight angle MQP:</u>

  • ∠MQP = ∠MQN + ∠RQN + ∠RQP
  • 180° = 4x + 4x + 2x
  • 10x = 180°
  • x = 18°

Correct choice is C

7 0
3 years ago
What is a common factor
katrin2010 [14]
When two numbers have a number in common for both that can be multiplied to get both numbers
5 0
3 years ago
What is the equation of the axis of symmetry?
Taya2010 [7]

Answer:

x=4

Step-by-step explanation:

the axis of symmetry always divides a parabola into two even parts from the vertex.

Find the value of the vertex (4,7)

since you need a vertical line to split a parabola, the equation is (x = )

Use the x value of the vertex (4)

x=4

6 0
3 years ago
A road has a 10° angle. To the nearest foot, find the increase in altitude of a car after driving 4,000 feet along the road.
ahrayia [7]
See the attached image

8 0
3 years ago
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