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Agata [3.3K]
2 years ago
14

Plz help me solve this.

= 2x - 5" alt="x^{2} = 2x - 5" align="absmiddle" class="latex-formula">
Solve using the quadratic formula.
Mathematics
1 answer:
FinnZ [79.3K]2 years ago
8 0

Step-by-step explanation:

{x}^{2}  = 2x - 5 \\  {x}^{2}  - 2x + 5 = 0 \\ here \: a = 1 \\ b =  - 2 \\ c = 5 \\ solution \: for \: x =  \frac{ - b + or -  \sqrt{ {b}^{2}  - 4ac} }{2a}  \\  x =  \frac{ -  - 2 +  \: or -  \sqrt{ {( - 2)}^{2} - 4 \times 1 \times 5 } }{2 \times 1}  \\  \frac{2 + or \:  -  \sqrt{4 - 20} }{2}  \\  = (2 +  \: or \:  -  \sqrt{ - 16}  ) \div 2 \\  \frac{2 + 4i}{2} or \frac{2 - 4i}{2}  \\ 1 + 2i \: or \: 1 - 2i \\ thank \: you

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