Question

Find the following trigonometric values.

Answer 1

Answer:

$\cos(150)\degree = -\frac{\sqrt{3}}{2}$

$\sin(150)\degree=\frac{1}{2}$

Step-by-step explanation:

Formulae used:

cos (180°-θ) = -cos θ

sin (80°-θ) = sin θ

Therefore,

$\cos(150)\degree = cos(180-30)\degree = -\cos(30)\degree = -\frac{\sqrt{3}}{2} \\\\\sin(150)\degree = sin(180-30)\degree = \sin(30)\degree = \frac{1}{2}$