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Nady [450]
3 years ago
6

Write the inequality in words 1/3n-10>22​

Mathematics
2 answers:
Sedbober [7]3 years ago
5 0
A third n minus 10 greater than twenty two
Amiraneli [1.4K]3 years ago
5 0

Answer:

10 is subtracted from a third of a number is greater than 22

Step-by-step explanation:

1/3n-10>22​

you subtract 10 from 1/3n

1/3 - 10 is greater than 22

so:

10 is subtracted from a third of a number is greater than 22

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Anna71 [15]

Answer:

  see below

Step-by-step explanation:

To convert the numbers to percentages, divide each number by the table total (80) and multiply by 100%. That is equivalent to multiplying each number by 1.25%. For example, 18·1.25% = 22.5% (middle table number).

5 0
3 years ago
BRAINLIEST!! If the area of ABC is D, give the expressions that complete the equation for the measure of angle C
kati45 [8]

Answer: m= 1+3

Step-by-step explanation:

Basic math helps.

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4 0
3 years ago
I need help i'm really stuck
Ivenika [448]

Answer:

8

Step-by-step explanation:

If the area is 32 and the formula for area of a triangle is base * height / 2, and you have base = 8 and height = x and area = 32, this would be:

8 * x / 2 = 32

Now, solve:

8x/2=32\\4x=32\\x=8

4 0
3 years ago
Read 2 more answers
It is desired to compare the hourly rate of an entry-level job in two fast-food chains. Eight locations for each chain are rando
notka56 [123]

Answer:

It can be concluded that at 5% significance level that there is no difference in the amount paid by chain A and chain B for the job under consideration

Step by Step Solution:

The given data are;

Chain A 4.25, 4.75, 3.80, 4.50, 3.90, 5.00, 4.00, 3.80

Chain B 4.60, 4.65, 3.85, 4.00, 4.80, 4.00, 4.50, 3.65

Using the functions of Microsoft Excel, we get;

The mean hourly rate for fast-food Chain A, \overline x_1 = 4.25

The standard deviation hourly rate for fast-food Chain A, s₁ = 0.457478

The mean hourly rate for fast-food Chain B, \overline x_2 = 4.25625

The standard deviation hourly rate for fast-food Chain B, s₂ = 0.429649

The significance level, α = 5%

The null hypothesis, H₀:  \overline x_1 = \overline x_2

The alternative hypothesis, Hₐ:  \overline x_1 ≠ \overline x_2

The pooled variance, S_p^2, is given as follows;

S_p^2 = \dfrac{s_1^2 \cdot (n_1 - 1) + s_2^2\cdot (n_2-1)}{(n_1 - 1)+ (n_2 -1)}

Therefore, we have;

S_p^2 = \dfrac{0.457478^2 \cdot (8 - 1) + 0.429649^2\cdot (8-1)}{(8 - 1)+ (8 -1)} \approx 0.19682

The test statistic is given as follows;

t=\dfrac{(\bar{x}_{1}-\bar{x}_{2})}{\sqrt{S_{p}^{2} \cdot \left(\dfrac{1 }{n_{1}}+\dfrac{1}{n_{2}}\right)}}

Therefore, we have;

t=\dfrac{(4.25-4.25625)}{\sqrt{0.19682 \times \left(\dfrac{1 }{8}+\dfrac{1}{8}\right)}} \approx -0.028176

The degrees of freedom, df = n₁ + n₂ - 2 = 8 + 8 - 2 = 14

At 5% significance level, the critical t = 2.145

Therefore, given that the absolute value of the test statistic is less than the critical 't', we fail to reject the null hypothesis and it can be concluded that at 5% significance level that chain A pays the same as chain B for the job under consideration

3 0
3 years ago
if a race is 10 kilometers long. marker will be placed at tje beginning and the end of the race-course and at each 500meter mark
777dan777 [17]
20 markers are needed to cover the 10 kilometers.
6 0
3 years ago
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