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3 years ago

Rewrite the following equation in standard form y-4=-5/2 (x+3)

Mathematics

1 answer:

blsea [12.9K]3 years ago

4 0

Answer:

y-4=-5/2x+6

y=-5/2x+6+4

y=-5/2x+10

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Using Cramer's Rule, what are the values of x and y in the solutio

olya-2409 [2.1K]

Answer:

x = -3, y = 1

Step-by-step explanation:

To find the value of x and y, find the determinant of original matrix, which would be 21.

Then, substitute the value of x with the solutions to the equations and find the determinant of that matrix, which is -63.

Cramer's rule says that Dx ÷ D is the value of x. So, -63 ÷ 21 = -3.

So, the x-value is -3.

You can find the determinant of the y-value in the same way, and you'll find out that y = 1.

Hope this helped! :)

8 0

3 years ago

Please help i will give you Brainlyist

Nataliya [291]

2 2/3 is an answer, your welcome

3 0

3 years ago

Please help ASAP thank youu!!

Gennadij [26K]

Answer:

1. (-5)

Step-by-step explanation:

Here you go, glad to help :)

4 0

3 years ago

A function is given. Determine the average rate of change of the function between the given values of the variable: f(x)= 4x^2;

nevsk [136]

$\bf slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ f(x_2)}}-{{ f(x_1)}}}{{{ x_2}}-{{ x_1}}}\impliedby 
\begin{array}{llll}
average\ rate\\
of\ change
\end{array}\\\\
-------------------------------$

$\bf f(x)= 4x^2 \qquad 
\begin{cases}
x_1=3\\
x_2=3+h
\end{cases}\implies \cfrac{f(3+h)-f(3)}{(3+h)~-~(3)}
\\\\\\
\cfrac{[4(3+h)^2]~~-~~[4(3)^2]}{\underline{3}+h-\underline{3}}\implies \cfrac{4(3^2+6h+h^2)~~-~~4(9)}{h}
\\\\\\
\cfrac{4(9+6h+h^2)~~-~~36}{h}\implies \cfrac{\underline{36}+24h+4h^2~~\underline{-~~36}}{h}
\\\\\\
\cfrac{24h+4h^2}{h}\implies \cfrac{\underline{h}(24+4h)}{\underline{h}}\implies 24+4h$

8 0

3 years ago

IF CORRECT ILL MARK U BRAINLIEST❤️

natulia [17]

Answer:

Step-by-step explanation:

y/x = 12/4 = 3

5 0

3 years ago

Read 2 more answers