A) Vf = Vo - g*t
Vf = 0
g = 9.8 m/s^2
Vo = g* t => t up = Vo / g
t total = 2*t = 2*Vo / g
t slow = 2*Vo / g
t fast = 2*[3Vo] / g = 6Vo / g => Vo = g * t fast / 6 = 9.8 m/s^2 * 8.00 s / 6 = 13.07 m/s = Vo
t slow = 2 * 13.07 m/s / 9.8 m/s^2 = 2.67 s.
B)
Vf ^2 = Vo ^2 - 2gy
Vf = 0 => Vo ^2 = 2gy
Vo ^2 = 2gH
[3Vo]^2 = 2gy
=> [3Vo]^2 / Vo^2 = 2gy / 2gH
=> 9 = y/H => y = 9H
Answer: 539.4 N
Explanation:
Let's begin by explaining that Coulomb's Law establishes the following:
"The electrostatic force
between two point charges
and
is proportional to the product of the charges and inversely proportional to the square of the distance
that separates them, and has the direction of the line that joins them"
What is written above is expressed mathematically as follows:
(1)
Where:
is the electrostatic force
is the Coulomb's constant
and
are the electric charges
is the separation distance between the charges
Then:
(2)
Isolating
and
:
(3)
Now, if we keep the same charges but we decrease the distance to
, (1) is rewritten as:
(4)
Then, the new electrostatic force will be:
(5) As we can see, the electrostatic force is increased when we decrease the distance between the charges.
Answer: 200m/min
Explanation:
Divide 10000m by 160m/min, you will get the answer 62.5. You then subtract 12.5 from 62.5 to understand what you will need your answer for the other person’s speed will be. 10000m divided by 50min is 200m/min.
Answer:
Check the explanation
Explanation:
(31)
induced EMF depends on change in angle

Answer is option (b) i.e.,rotating the loop about an axis perpendicular to the field lines
(31) True
Induced emf. 

<h2>Speed = Distance/Time</h2>
If a train travelled 500 meters in 25 seconds then,
Speed = 500m/25sec
<h2>
→ 20 m/sec</h2>
