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Bas_tet [7]
3 years ago
9

NEED HELP

Physics
1 answer:
ch4aika [34]3 years ago
8 0

Answer: C.

Explanation:

Just took quiz

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How far apart are two conducting plates that have an electric field strength of 8.53 x 103 V/m between them, if their potential
sleet_krkn [62]

Answer:

d=2.7m

Explanation:

From the question we are told that:

Electric Field strength E=8.53 * 10^3 V/m

Potential difference is V= 23.0 kV

Generally the equation for distance is mathematically given by

d=\frac{V}{E}

d=\frac{23.0*10^3}{8.53 * 10^3 V/m}

d=2.7m

5 0
3 years ago
Relative to the ground, what is the gravitational potential energy of 68 kg
Kisachek [45]

Answer:

Explanation:

p.E=mgh

P.E=68*10*443

p.E=301240j

8 0
2 years ago
If2.0J of work is done in raising a 180g apple how far is it lifted?
Alex
We know, W = F * s
W = mg * s

Here, w = 2 J
m = 180 g = 0.180 Kg
g = 9.8 m/s

Substitute their values into the expression:
2 = 0.180*9.8 * s
1.764s = 2
s = 2 / 1.764
s = 1.13 meter

In short, Your Final Answer is 1.13 m

Hope this helps!

7 0
3 years ago
Look at the image and answer the question correctly.
mart [117]

Answer:

B

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