b. is equally as toxic as carbon monoxide (CO).
Explanation:
Hydrogen Cyanide is a product of combustion that is equally as toxic as carbon monoxide CO.
The gas is a product of combustion in blast furnances, coke ovens, e.t.c
- Just like carbon monoxide, they are blood agents that are toxic in the body
- Prolonged exposure to hydrogen cyanide can lead to death eventually.
- The gas is a able to produce cyanide ion that seriously impacts the process of cellular respiration and bringing it to a halt.
- It is listed as one of the dangerous chemical weapons.
Learn more:
Safety data sheets brainly.com/question/2188622
#learnwithBrainly
Answer: Extinction
Explanation: Extinction simply means cessation. A condition whereby an action or behavior exhibited by an individual or organism eventually stops. In psychological parlance, extinction is usually attributed to the discontinuance of a certain behavior usually due to non - reinforcement or eventual absence of the conditioned stimulus.
In the scenario above, the point at which Mary stopped sneezing is called extinction which is due to the removal of the cat which is the cause of Mary's sneezing behavior.
The time period of oscillation is 3.04×10
what is time period?
A time period (denoted by 'T'' ) is the time taken for one complete cycle of vibration to pass a given point.[1] As the frequency of a wave increases, the time period of the wave decreases. The unit for time period is 'seconds'.
The related parameters are oscillation frequency and period.They are the opposite of the another.As a result the formula to be used is
frequency=1/time
given:
Frequency of oscillation=32.8khz=32800hz
therefore,
time period of oscillation=1/32800hz
time period of oscillation=3.04×10
learn more about oscillation from here: brainly.com/question/28167898
#SPJ4
U = 0, initial upward speed
a = 29.4 m/s², acceleration up to 3.98 s
a = -9.8 m/s², acceleration after 3.98s
Let h₁ = the height at time t, for t ≤ 3.98 s
Let h₂ = the height at time t > 3.98 s
Motion for t ≤ 3.98 s:
h₁ = (1/2)*(29.4 m/s²)*(3.98 s)² = 232.854 m
Calculate the upward velocity at t = 3.98 s
v₁ = (29.4 m/s²)*(3.98 s) = 117.012 m/s
Motion for t > 3.98 s
At maximum height, the upward velocity is zero.
Calculate the extra distance traveled before the velocity is zero.
(117.012 m/s)² + 2*(-9.8 m/s²)*(h₂ m) = 0
h₂ = 698.562 m
The total height is
h₁ + h₂ = 232.854 + 698.562 = 931.416 m
Answer: 931.4 m (nearest tenth)
