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Anna71 [15]
3 years ago
15

Select the correct answer.

Physics
1 answer:
natulia [17]3 years ago
7 0

Answer:

the power of pardon

Explanation:

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1.the student measures the mass of a piece of metal.its mass is 146g.
marissa [1.9K]

Answer:

7.3 g/cubic cm

Explanation:

You divide the mass by the volume to calculate the density of the metal.

146g ÷ 20cm³ = 7.3g/cm³

3 0
3 years ago
11. (a)What downward force is acting on you when you go down a waterslide? (b)What type of friction is
statuscvo [17]

Answer:

a) "gravitation" is the force causing you to go down a waterslide

b) It is "fluid friction" as a solid object (our body) moves over a fluid (the water)

c) It would become "sliding friction" since two solid surfaces slide over each other

d) fluid friction being the weakest friction, switching to sliding friction means a higher decrease in speed and therefore removing the water from a slide will decrease our speed

3 0
2 years ago
What area of the earth contains semi-solid rock and lava
katrin2010 [14]

Answer:

mantle

Explanation:

Below the crust lies a layer of very hot, almost solid rock called the mantle. Beneath the mantle lies the core. The outer core is a liquid mix of iron and nickel, but the inner core is solid metal. Sometimes, hot molten rock, called magma, bursts through Earth's surface in the form of a volcano.

6 0
2 years ago
What is a work out time setting? (Gym)
tigry1 [53]

Answer:

It determines how long you do a certain workout.

3 0
3 years ago
A submarine is stranded on the bottom of the ocean with its hatch 21.0 m below the surface. calculate the force (in n) needed to
Tanzania [10]

Answer:

28,400 N

Explanation:

Let's start by calculating the pressure that acts on the upper surface of the hatch. It is given by the sum of the atmospheric pressure and the pressure due to the columb of water, which is given by Stevin's law:

p_{top} = p_{atm} + \rho g h=1.013\cdot 10^5 Pa + (1000 kg/m^3)(9.8 m/s^2)(21.0 m)=3.071 \cdot 10^5 Pa

On the lower part of the hatch, there is a pressure equal to

p_{bot}=p_{atm}=1.013\cdot 10^5 Pa

So, the net pressure acting on the hatch is

p=p_{top}-p_{bot}=3.071 \cdot 10^5 Pa - 1.013\cdot 10^5 Pa=2.058 \cdot 10^5 Pa

which acts from above.

The area of the hatch is given by:

A=\pi r^2 = \pi (\frac{0.420 m}{2})^2=0.138 m^2

So, the force needed to open the hatch from the inside is equal to the pressure multiplied by the area of the hatch:

F=pA=(2.058\cdot 10^5 Pa)(0.138 m^2)=28,400 N

8 0
3 years ago
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