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tatiyna
3 years ago
11

Use the following figure to answer the question.

Mathematics
2 answers:
lianna [129]3 years ago
8 0

Answer:

corresponding

Step-by-step explanation:

The answer is corresponding if you want i can share my work.

Mkey [24]3 years ago
4 0

Answer:

corresponding

Step-by-step explanation:

because they are in the same place on both intersections. now if u ask me doggo deserve breinliest pwease ;-;

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My duvet cover is red . Statement or not
leva [86]

Answer:

It's definitely a statement

4 0
3 years ago
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Mariana gets $15 per hour working at McDonald's and Jayvon gets $15 per hour as well. Jayvon had $50 in the
zhannawk [14.2K]

Answer:

What r the options?

Step-by-step explanation:

3 0
3 years ago
On a coordinate plane, a line goes through (0, negative 1) and (3, 1). a point is at (negative 3, 0). what is the equation of th
Vitek1552 [10]

Required Equation is y = \frac{2x}{3}+2

Given: A line passing through ({x}_1,{y}_1) and ({x}_2,{y}_2)

Slope = \frac{(y_2 - y_1)}{(x_2 - x_1)} = \frac{( 1 - (-1))}{(3 - 0)}= \frac{2}{3}

Equation of line is:

Y_1(x) = \frac{2}{3}x + b

Where b is y intercept

for value of b

Y_1(0) = -1 = \frac{2}{3}*0 + b = b

⇒ b = -1

and Equation of line is:

Y_1(x) = \frac{2}{3}x + (-1)

For another parallel line that passes through the point (-3,0)

Y_2(x)= \frac{2}{3}x + c

Y_2(-3) = 0 = {2}{3}*-3 + c = -2 + c = 0

c = 2

then the equation is:

Y_2(x) = \frac{2}{3}x + 2

To learn more, visit:

brainly.com/question/14013431

#SPJ4

5 0
2 years ago
1. Construct a table of values of the following functions using the interval of 5
Morgarella [4.7K]

Complete Question:

Construct a table of values of the following functions using the interval of -5 to 5.

g(x) = \frac{x^3 + 3x - 5}{x^2}

Answer:

See Explanation

Step-by-step explanation:

Required

Construct a table with the given interval

When x = -5

g(x) = \frac{x^3 + 3x - 5}{x^2} becomes

g(-5) = \frac{-5^3 + 3(-5) - 5}{-5^2}

g(-5) = \frac{-125 -15 - 5}{25}

g(-5) = \frac{-145}{25}

g(-5) = -5.8

When x = -4

g(x) = \frac{x^3 + 3x - 5}{x^2} becomes

g(-4) = \frac{-4^3 + 3(-4) - 5}{-4^2}

g(-4) = \frac{-64 -12 - 5}{16}

g(-4) = \frac{-81}{16}

g(-4) = -5.0625

When x = -3

g(x) = \frac{x^3 + 3x - 5}{x^2} becomes

g(-3) = \frac{-3^3 + 3(-3) - 5}{-3^2}

g(-3) = \frac{-27 -9 - 5}{9}

g(-3) = \frac{-41}{9}

g(-3) = -4.56

When x = -2

g(x) = \frac{x^3 + 3x - 5}{x^2} becomes

g(-2) = \frac{-2^3 + 3(-2) - 5}{-2^2}

g(-2) = \frac{-8 -6 - 5}{4}

g(-2) = \frac{-19}{4}

g(-2) = -4.75

When x = -1

g(x) = \frac{x^3 + 3x - 5}{x^2} becomes

g(-1) = \frac{-1^3 + 3(-1) - 5}{-1^2}

g(-1) = \frac{-1 + 3 - 5}{1}

g(-1) = \frac{-3}{1}

g(-1) = -3

When x = 0

g(x) = \frac{x^3 + 3x - 5}{x^2} becomes

g(0) = \frac{0^3 + 3(0) - 5}{0^2}

g(0) = \frac{0 + 0 - 5}{0}

g(0) = \frac{- 5}{0}

<em>g(0) = undefined</em>

When x = 1

g(x) = \frac{x^3 + 3x - 5}{x^2} becomes

g(1) = \frac{1^3 + 3(1) - 5}{1^2}

g(1) = \frac{1 + 3 - 5}{1}

g(1) = \frac{-1}{1}

g(1) = 1

When x = 2

g(x) = \frac{x^3 + 3x - 5}{x^2} becomes

g(2) = \frac{2^3 + 3(2) - 5}{2^2}

g(2) = \frac{8 + 6 - 5}{4}

g(2) = \frac{9}{4}

g(2) = 2.25

When x = 3

g(x) = \frac{x^3 + 3x - 5}{x^2} becomes

g(3) = \frac{3^3 + 3(3) - 5}{3^2}

g(3) = \frac{27 + 9 - 5}{9}

g(3) = \frac{31}{9}

g(3) = 3.44

When x = 4

g(x) = \frac{x^3 + 3x - 5}{x^2} becomes

g(4) = \frac{4^3 + 3(4) - 5}{4^2}

g(4) = \frac{64 + 12 - 5}{16}

g(4) = \frac{71}{16}

g(4) = 4.4375

When x = 5

g(x) = \frac{x^3 + 3x - 5}{x^2} becomes

g(5) = \frac{5^3 + 3(5) - 5}{5^2}

g(5) = \frac{125 + 15 - 5}{25}

g(5) = \frac{135}{25}

g(5) = 5.4

<em>Hence, the complete table is:</em>

x  ---- g(x)

-5 --- -5.8

-4 --- -5.0625    

-3 --- -4.56

-2 --- -4.75  

-1 --- -3

0 -- Undefined

1 --- 1

2 -- 2.25

3 --- 3.44

4 --- 4.4375

5 --- 5.4

7 0
3 years ago
HELP ASAP I’ll reward most brainlyestttttt
PolarNik [594]

Answer:

y = 2/3 x + 2

Slope intercept form is the form of y=mx + b.

The slope is 2/3, so that is m, and from looking at the graph, we know that the y intercept is (0,2), so b has the value of 2.

I hope this helps! Please let me know if you have any more questions!

4 0
3 years ago
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