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Fynjy0 [20]
3 years ago
6

Plants appear green because they do not absorb the green wavelengths of light. What happens to those green light waves when they

hit a plant? The are diffracted. They are absorbed. They are reflected. They are refracted.
Physics
2 answers:
KonstantinChe [14]3 years ago
8 0

Answer:

They are reflected.

Explanation:

Red light is absorbed while green light is reflected, causing the color to be green in human eyes.

Readme [11.4K]3 years ago
6 0

Answer:

c

Explanation:

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If x =(20-4t^2) find average velocity between t=0and t=2sec​
lapo4ka [179]

Answer:

The average velocity is 8 unit per sec

Explanation:

Given as :

The Distance x = 20 - 4t²  unit

Change in time Δt = ( 2 - 0 ) s = 2 s

Let the velocity = V unit/s

∴   V = \frac{\partial (20 - 4t^{2})}{\partial x}

Or, V =  - 8t          unit/s

Now velocity at t = 0

V1 = - 8 × 0 =  0  unit/s

And   velocity  at t = 2 sec

V2 =  - 8 × 2 = - 16

So, Average velocity = \frac{v2 - v1}{2} = \frac{- 16 - 0}{2} = -8

Or, \begin{vmatrix}V\end{vmatrix} = 8   unit/sec

Hence The average velocity is 8 unit per sec       Answer

6 0
3 years ago
An experiment is designed to test what color of light will activate a photoelectric cell the best. The photocell is set in a cir
Mariana [72]

Answer:

the color of the light after it has passed through the cellophane

Explanation:

Since in the given experiment, there is an impact of various colors of light on the cell i.e. photoelectric that should be measured. The photocell should be placed in a circuit when the current would passed. For every color that falls on the photocell, the value of the current that passed via the cell represent an idea.

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6 0
3 years ago
45 POINTS
Kamila [148]

The elastic potential energy in the spring is 1 J

Explanation:

The elastic potential energy stored in a spring is given by:

U=\frac{1}{2}kx^2

where

k is the spring constant

x is the stretching/compression of the spring with respect to the unstretched length

For the spring in this problem, we have:

k = 200 N/m is its spring constant

The spring is stretched by 5.0 cm first and then by an additional 5.0 cm, so the total stretching is

x=5.0 + 5.0 = 10.0 cm = 0.10 m

Therefore, the elastic potential energy in the spring is:

U=\frac{1}{2}(200)(0.10)^2=1 J

#LearnwithBrainly

6 0
3 years ago
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