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3 years ago

What mass of CO2 is needed to fill an 80.0 L tank to a pressure of 150.0 atm at 27.0°C?

1 answer:

6 0

We know that:
PV = nRT
and n = mass/Mr
PV = mRT/Mr
m = PVMr/RT
m = (150 x 101325)(80 x 10⁻³)(44) / [(8.314 x (27 + 273)]
m = 21,449 kg of CO₂

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Use differentials to estimate the amount of metal in a closed cylindrical can that is 10 cm high and 10 cm in diameter if the me

lana66690 [7]

Answer:

dV = 32.98 cm³

Explanation:

We know that

V = f ( h,r)

$dV= \frac{\partial V}{\partial r}dr+ \frac{\partial V}{\partial h}dh$

We also know that

$V=\pi r^2h$

$dV= 2\pi h dr + \pi r^2 dh$

Given that

h= 10 cm

d=10 cm , r= 5 cm

Thickness = 0.05 cm so dr = 0.05 cm

The metal in the top and the bottom is 0.2 cm thick so dh = 0.2 + 0.2 cm

dh = 0.4 cm

Now by putting the values

$dV= 2\pi h dr + \pi r^2 dh$

$dV= 2\times \pi \times 5\times 0.05 + \pi \times 5^2\times 0.4\ cm^3$

dV = 32.98 cm³

8 0

3 years ago

What is the external-internal pressure difference when the diver's lungs are at a depth of 6.1m (about 20ft)? assume that the di

Nesterboy [21]

Snorkel connects the diver's lungs with the air above the water. Because of this, the pressure inside the diver's lungs is the same as the atmospheric pressure.
The static pressure of a fluid is given with this equation:
$P=\rho gh$
The density of water is 1000kg/m^3.
$P=1000\cdot 9.81 \cdot 6.1=59841$Pa$
Standart atmospheric pressure is 101<span>325Pa.
</span>The difference is:
$\Delta P=101325-59841=41484 $Pa$

8 0

3 years ago

a 2 kg block of ice is pushed along the ground with a constant 10 n force assuming there is no friction what is the acceleration

Sergio039 [100]

According to Newton’s second law acceleration= force/mass

So acceleration = 10/2
= 5m/s^2

3 0

3 years ago

Which of the following changes would double the force between two charged particles? O A. Decreasing the distance between the pa

jarptica [38.1K]

Let's check

$\\ \rm\dashrightarrow F=\dfrac{k}{q_1q_2}{r^2}$

$\\ \rm\dashrightarrow F\propto Q$

$\\ \rm\dashrightarrow F\propto \dfrac{1}{r^2}$

Option A and C can be used

6 0

2 years ago

Read 2 more answers

You have 9 stones that are identical in appearance. One of these stones weighs just a bit more than the other 8. These other 8 s

Lynna [10]

I think you can weigh it 3 and 3.
If they balance, choose set not used.

If not balanced, take the heavier side

then weigh 1 and 1
if balanced, stone not used, if not balanced, take the heavier side

hope this helps

8 0

3 years ago