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3 years ago

In which situation does Newton’s third law play a role?

Physics

2 answers:

yanalaym [24]3 years ago

7 0

Answer: B

Explanation:

DaniilM [7]3 years ago

6 0

B because for every action, there is an opposite reaction (Which is Newton’s third law)

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If an R = 1-kΩ resistor, a C = 1-μF capacitor, and an L = 0.2-H inductor are connected in series with a V = 150 sin (377t) volts

fgiga [73]

Answer

given,

R = 1-kΩ = 1000 Ω

C = 1-μF

L = 0.2-H

V = V_max sin( ω t)

comparing

V = 150 sin ( 377 t)

ω = 377

$\chi_c = \dfrac{1}{\omega C}$

$\chi_c = \dfrac{1}{377 \times 1 \times 10^{-6}}$

$\chi_c = 2652.5\Omega$

$\chi_L =377 \times 0.2$

$\chi_L =75.4\ \Omega$

Impedance,

$Z = \sqrt{R^2+(\chi_L-\chi_c)^2}$

$Z = \sqrt{1000^2+(75.4 -2652.5)^2}$

Z = 2764.3 Ω

now,

V_{max} = 150 V

$I_{max} = \dfrac{V}{Z}$

$I_{max} = \dfrac{150}{2764.3}$

$I_{max} = 0.0543$

$I_{max} = 54.3\ mA$

3 0

3 years ago

Britney is aware of the thoughts running through her mind and the emotions triggered by some of those thoughts. She is also awar

Sonbull [250]

Answer:

Consciousness

Explanation:

Obstructionism is the philosophy which dictates that a process needs to be delayed or stopped from occurring.

Transcendence means to achieve a state higher than the previous state.

Hyperkinesis is the condition where a person is unable to concentrate on something and is hyperactive.

Consciousness is the state from which an organism knows their existence and is aware of things that are present externally. Here, Britney is aware of her existence and the existence of other things around her.

Hence, she would be considered to be in a state of Consciousness

3 0

4 years ago

Choose the best description of the attraction between you and your classmate.

Lerok [7]

Answer:

The correct option is;

D. There is not enough information to answer this question

Explanation:

The universal gravitational constant = 6.67408 × 10⁻¹¹ 3³/(kg·s²)

For an in between distance of 1 m and equal masses of 60 kg, we have;

$F = G \times \dfrac{m_{1} \times m_{2}}{r^{2}} = 6.67408 \times 10^{-11} \times \dfrac{60 \times 60}{1^{2}} \approx 2.403 \times 10^{-7} N$

The gravitational attraction ≈ 2.403 × 10⁻⁷ N, which does not correspond with the answers, therefore, the best option is that there is not enough information to answer this question.

5 0

3 years ago

A given mass of air has a volume of 6.00 L at 101 kPa. At constant temperature, the pressure is decreased to 25.0 kPa. Calculate

Sidana [21]

Answer:

24.24L

Explanation:

According to Boyle's law which states that "the volume of a given mass of gas at constant temperature is inversely proportional to its pressure". Mathematically, P = k/V where;

P is the pressure

V is the volume

k is the proportionality constant

PV = k

P1V1 = P2V2

P1 and P2 are initial and final pressure respectively

V1 and V2 are the initial and final volume respectively

Given P1 = 101kPa V1 = 6.0L, P2 = 25kPa V2 = ?

From the formula;

V2 = P1V1/P2

V2 = 101×6/25

V2 = 24.24L

The final volume for the gas is 24.24L

6 0

4 years ago

Contrast the image formed by a convex lens when an object is located more than twice the focal length from the lens with the ima

matrenka [14]

Answer:

$\begin{array}{lll}&\underline{Object \ at \ more \ than \ 2\times Focus} & \underline{Object \ at \ less \ than \ Focus}\\\\1. \ Location \ of \ image &Same \ side \ as \ object&Opposite \ side \ of \ lens\\\\2. \ Orientation \ of \ image &Inverted&Upright\\\\3. \ Type \ of \ image&Real&Virtual\\\\4. \ Size\ of \ image&Smaller \ than \ object& Larger \ than \ object\end{array}$

Explanation:

The location, orientation, size, and type of image formed by a convex lens are related to the position of the image location in front of the lens

Object >2·F = The image formed by a convex lens when the object is located more than twice the focal length from the lens

Object < F = The image formed by the convex lens when the object is located between the lens and the focal length

$\begin{array}{lll}&\underline{Object \ > \ 2\cdot F} & \underline{Object < F}\\\\1. \ Location \ of \ image &Same \ side \ as \ object&Opposite \ side \ of \ lens\\\\2. \ Orientation \ of \ image &Inverted&Upright\\\\3. \ Type \ of \ image&Real&Virtual\\\\4. \ Size\ of \ image&Smaller \ than \ object& Larger \ than \ object\end{array}$

8 0

3 years ago