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levacccp [35]
3 years ago
14

A cheetah attends the speed of 110 km per hour but the fastest human Sprinter goes a hundred meters in 9.58 seconds. How many ti

mes faster is the cheetah than the human sprinter
Mathematics
1 answer:
poizon [28]3 years ago
5 0

Answer:

73.27 km/hr

Step-by-step explanation:

The fastest human sprinter sprints 100 metres in 9.58 seconds. Thus, speed of sprinter is;

V_sprinter = 100/9.8

V_sprinter = 10.204 m/s

Now, from conversion, 1 m/s = 3.6 km/hr

Then, 10.204 m/s = (10.204 × 3.6)/1 = 36.73 km/h

The cheetah sprints 110 km/hr

Thus, the cheetah is faster by: 110 - 36.73 = 73.27 km/hr

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Answer:

Y=s^2/36 and y=5.7;14.3 ft

Step-by-step explanation:

The question was not typed correctly. Here, a better version:

<em>The aspect ratio is used when calculating the aerodynamic efficiency of the wing of a plane for a standard wing area, the function A(s)=s^2/36 can be used to find the aspect ratio depending on the wingspan in feet. If one glider has an aspect ratio of 5.7, which system of equations and solution can be used to represent the wingspan of the glider? Round solution to the nearest tenth if necessary.  </em>

<em> </em>

<em>Y=s^2/36 and y=5.7;14.3 ft </em>

<em>Y=5.7s^2 and y=36; s=2.5ft </em>

<em>Y=36s^2 and y=0; s=0.4 ft </em>

<em>Y=s^2/36 +5.7 and y=0; s=5.5 ft</em>

In the function A(s)=s^2/36 A(s) represents the aspect ratio and s the wingspan. If one glider has an aspect ratio of 5.7, then A(s) = 5.7. We want to know the wingspan of the glider. Replacing A(s) by Y we get the following system of equation:

Y=s^2/36    

with y = 5.7

5.7 = s^2/36    

5.7*36 =  s^2

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