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ANEK [815]
2 years ago
5

What is the inerquartile range of 29, 30, 28, 32, 28, 31, 27

Mathematics
1 answer:
Digiron [165]2 years ago
4 0
Put them in order 27 28 28 29 30 31 32 Q1 is 28, Q2 is 29, Q3 is 31, interquartile range is Q3-Q1 if i’m not mistaken so the answer is 3
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What formula could I use to solve this ?<br> Using f(x) =-3+7 <br> What is x when f(x) = -20
UNO [17]

Answer:

x = 9

Step-by-step explanation:

I think you wrote the question wrong (I am assuming that there is a x next to the -3).

Subtract 7

-27 = -3x

divide by -3

9 = x

5 0
2 years ago
D = b^2 -4ac solve for a 2/3 (x-18y) = 6y solve for x
seropon [69]

Answer:

a = \frac{b^2-d}{4c}

x = 27y

Step-by-step explanation:

Order of Operations: BPEMDAS

<u>Question 1</u>

Step 1: Write out discriminant

d = b² - 4ac

Step 2: Subtract b² on both sides

d - b² = -4ac

Step 3: Divide both sides by -1

b² - d = 4ac

Step 4: Divide both sides by 4c

a = \frac{b^2-d}{4c}

<u>Question 2</u>

Step 1: Write out equation

2/3(x - 18y) = 6y

Step 2: Distribute parenthesis

2/3x - 12y = 6y

Step 3: Isolate <em>x </em>by adding 12y on both sides

2/3x = 18y

Step 4: Divide both sides by 2/3

x = 27y

7 0
2 years ago
HELP ASAP INCLUDE WORK I WILL MARK BRAINLIEST
Troyanec [42]
Step 1 is to find how far apart W and Y are:
-7 - (-31) = 24

Now find 1/8 of that distance: 1/8 • 24 = 3

Now move 3 units from -31 towards -7: -31 + 3 = -28
3 0
2 years ago
I need help on this problem. I got half of it right but I don’t know how I got the last answer wrong... Can anyone please help m
morpeh [17]
I got the same answer as you. Try to ask your teacher about it since it’s a math problem online or something.
8 0
3 years ago
The length of a rectangle is 5 less than 3 times its width. The perimeter is
My name is Ann [436]

Answer:

The length is 28 and the width is 11

Step-by-step explanation:

To solve this problem, we can make the width as x.

Since the length is 5 less than 3 times the width, it's going to be 3x - 5

So now we've got the length and width, just need to find the perimeter, which is all the sides added up together. They already gave us the perimeter, so we just have to solve the equation:

2(3x - 5) + 2x = 78

6x - 10 + 2x = 78

8x - 10 = 78

8x = 88

x = 11

x = 11, but remember, x is the width, not the length. Since we already found what x is, we just have to plug it into the equation of:

3x - 5

3 × 11 - 5

33 - 5 = 28

Answer: Length = 28 (don't forget to add the unit if there is one)

8 0
2 years ago
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