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3 years ago

If 10.23 moles of NH3 were produced, how many moles of N2 would be required?

Chemistry

1 answer:

Dima020 [189]3 years ago

3 0

Answer:

the number of moles of N_2 required is 5.12 moles

Explanation:

The computation of the number of moles of N_2 required is shown below:

N₂ + 3H₂ → 2NH₃

Here the nitrogen moles and hydorgen would be compared

NH₃ : N₂

2 : 1

10.23 : 1 ÷ 2 × 10.23 = 5.12mol

Hence, the number of moles of N_2 required is 5.12 moles

Therefore the same would be considered and relevant too

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Please help with this question

tamaranim1 [39]

1.806x10^24
Written equation form(always start the equation off with what you know based off of the question!):

3mol(CCl4)•6.022x10^23/1mol = 1.806x10^24

Good luck!

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3 years ago

Which of the following is a cause of eutrophication of a lake?

cluponka [151]

Answer:

storm runoff

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4 0

3 years ago

Read 2 more answers

When copper is changed to copper(II) nitrate by the nitric acid, it is an example of a(n) ______-_______ reaction. (two words, i

Nataly_w [17]

Answer:

oxidation- reduction

Explanation:

where gaining electronic reduces one element and losing them oxidize the other nitric acid is not only strong it is also a oxidizing agent

<h2>Oxidize: copper = Cu+2</h2>

5 0

3 years ago

How many objects are in a mole of objects?

lakkis [162]

Your Question: {How many objects are in a mole?}

Helpful Knowledge: (We Know the amount in an object: 12g or C^12)

{A number of objects that are in a mole of objects?}

Well for the question it is pretty easy to answer because a number of objects in One mole would equal 6.02 × 10²³

Which 6.02 × 10²³ is an Avogadro's Number.

So it depends on how many objects you have.

So for every object you have, One mole would equal 6.02 × 10²³. Or 62,000,000,000,000,0000,000,000. Big Number am I right. So that's why we just use 6.02 × 10²³.

Anywho, your answer would be 6.02 x 10²³ x n.
N would equal the number of objects you're calculating.

Final Answer: 6.02 x 10²³ x (n) = (Your Answer)

Hope this helps! Have a great day. If you need anything else, feel free to hope right in my inbox. Or comment below. ↓

6 0

3 years ago

Wolff-kishner reduction (hydrazine, koh, ethylene glycol, 130°c) of the compound shown gave compound

telo118 [61]

The scheme is shown below, the steps involved are as follow,

Step one: Reduction:
The carbonyl group of given compound on reduction using Wolf Kishner reagent converts the carbonyl group into -CH₂- group.

Step two: Epoxidation:
The double bond present in starting compound when treated with m-CPBA (<span>meta-Chloroperoxybenzoic acid) gives corrsponding epoxide.

Step three: Reduction:
The epoxide is reduced to alcohol on treatment with Lithium Aluminium Hydride (LiAlH</span>₄)<span> followed by hydrolysis.

Step four: Oxidation:
The hydroxyl group (alcohol) is oxidized to carbonyl (ketonic group) using oxidizing agent Chromic acid (H</span>₂CrO₄).

8 0

3 years ago