Question

If 10.23 moles of NH3 were produced, how many moles of N2 would be required?

Answer 1

Answer:

the number of moles of N_2 required is 5.12 moles

Explanation:

The computation of the number of moles of N_2 required is shown below:

N₂ +  3H₂ → 2NH₃

Here the nitrogen moles and hydorgen would be compared  

NH₃  :  N₂

2 :  1

10.23  : 1 ÷ 2 × 10.23 = 5.12mol

Hence, the number of moles of N_2 required is 5.12 moles

Therefore the same would be considered and relevant too