Individual differences in a group is called what

Chemistry question. Image attached.

Stells [14]

Answer:

The answer to your question is given below

Explanation:

The balanced equation for the reaction is given below:

CaO(s) + CH4(g) + 2H2O(g) <=> CaCO3(s) + 4H2(g)

1. Writing an expression for the equilibrium constant, K.

The equilibrium constant, K for a reaction is simply the ratio of the concentration of the products raised to their coefficient to the concentration of the reactants raised to their coefficient.

Thus, we can write the equilibrium constant, K for the reaction as follow:

CaO(s) + CH4(g) + 2H2O(g) <=> CaCO3(s) + 4H2(g)

K = [CaCO3] [H2]⁴ / [CaO] [CH4] [H2O]²

2. Based on the value of K, more products will be in the equilibrium mixture since the value of K is a positive large number.

6 0

3 years ago

Can anyone give me tips on how to present 4-6 mark questions in science assessments? I understand the logic but I find it hard t

Vlad1618 [11]

Answer:

- start by recycling the question

- explain the topic using key words related to that topic

- include a few examples/data if it's using a graph/photo

5 0

3 years ago

Nicotine, a component of tobacco, is composed of c, h, and n. A 2.625-mg sample of nicotine was combusted, producing 7.1210 mg o

Vikki [24]

The mass sample of nicotine combusted = 2.625 mg (given)

Mass of $CO_2$ produced = 7.1210 mg (given)

Mass of $H_2O$ produced = 2.042 mg (given)

Molar mass of $CO_2$ = 44 g/mol

Molar mass of $H_2O$ = 18 g/mol

Percentage of Carbon = $\frac{12 g}{44 g/mol}\times \frac{7.120 mg of CO_2}{2.625 mg sample}\times 100 = 74.04$ %

Percentage of hydrogen = $\frac{2 g}{18 g/mol}\times \frac{2.04 mg of H_2O}{2.625 mg sample}\times 100 = 8.62$ %

Now, for percentage of nitrogen = $100 - (74.04+8.62) = 17.34$ %

Calculating the moles of each element:

$Number of moles = \frac{given mass}{Molar mass}$

For $C$

$\frac{74.04 g}{12 g/mol} = 6.17 mol$

For $H$

$\frac{8.62 g}{1 g/mol} = 8.62 mol$

For $N$

$\frac{17.34 g}{14 g/mol} = 1.24 mol$

Dividing with the smallest mole value to calculate the molar ratio of each element:

$C_{\frac{6.17}{1.24}} = C_{4.9} = C_5$

$H_{\frac{8.62}{1.24}} = H_{6.9} = H_7$

$N_{\frac{1.24}{1.24}} = N_1$

Hence, the empirical formula for nicotine is $C_5H_7N$ .

8 0

3 years ago

I'll give brianliest if correct .

Tresset [83]

Answer:

the answer is decaying wood

3 0

3 years ago

Difference between covalent compound and binary ionic compound

Virty [35]

The main difference between a covalent compound and an ionic compound is the type of elements used. In a covalent compound, a nonmetal bonds with another nonmetal (e.g. H20, NH3, CH4).

In an ionic compound, a metal bonds with a nonmetal (e.g.NaCl, KCl, MgCl2). What makes an ionic compound binary is the amount of atoms used. This includes any ionic compounds that has two atoms such as NaCl and KCl.

Note that although MgCl2 has two elements, it does not have the same amount of atoms. Mg is one atom and Cl has a subscript of 2 which makes chlorine have two atoms.

Hope this helps!!!

4 0

3 years ago