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2 answers:
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Answer:
LAOD = 6669.86 N
Explanation:
Given data:
width
thickness
crack length 2c = 0.5 mm at centre of specimen
stress intensity factor = k will be
we know that
[c =0.5/2 = 2.5*10^{-4}]
K = 0.1724 Mpa m^{1/2} for 1000 load
if then load will be
LAOD = 6669.86 N