Traveling a average speed at 55mph how many miles will you travel in9 hours
1 answer:
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Answer:
The total system active power P = P_1 + P_2 + P_3 = 34.91 KW
Explanation:
Load 1: Active power P_1 = 20 HP = 14.91kW;
Reactive power
Load 2: Active power P_2 = 20 kW;
Reactive power Q2 = 0 since the load is purely resistive.
Load 3: Active power = 0 due to purely capacitiveload
Reactive power = -20 Var
a) since all three loads are connected in parallel therefore
The total system active power P = P_1 + P_2 + P_3 = 34.91 KW
Total system reactive power Q = Q_1 + Q_2 + Q_3 = 11.18 + 0 -20 = -8.82 kVar
Since Q = 0, the power factor is unity.
Supply current per phase is given by
Answer:
import java.util.Scanner;
import java.io.*;
public class Main{
public static void main(String []args){
StringBuilder reversedName = new StringBuilder();
StringBuilder subName = new StringBuilder();
Scanner myObj = new Scanner(System.in); // Create a Scanner object
System.out.println("Enter your full name (last name + first name)");
String name = myObj.nextLine(); // Read user input
for (int i = 0; i < name.length(); i++) {
char currentChar = name.charAt(i);
if (currentChar != ' ') {
subName.append(currentChar);
} else {
reversedName.insert(0, currentChar + subName.toString());
subName.setLength(0);
}
}
String Resul = reversedName.insert(0, subName.toString()).toString();
System.out.println("Reverse full name: " + Resul);
}
}
Explanation:
To solve the problem we used StringBuilder, that allow us to build a string letter by letter, we are using two, one to store temporary information (subName) and the other to store the surname plus name (reversedName). After defining the variables, the program asks for the user fullname using Scanner class and it's method .nextLine (the variable 'name' will save the user input). A while loop is also used to iterate over the name, taking character by character with the method .charAt, the program will append letters in subName until it finds a space only then the content of subName will be transfer to reversedName and the content of subName will be deleted, then the program continues with the process until the end of the for loop; finally, the program places the content of subName at the beginning of reversedName, and print the result transforming the StringBuilder to a normal string.
Answer:
The power of force F is 115.2 W
Explanation:
Use following formula
Power = F x V
= F cos0
= (30) x 4/5
= 24N
Now Calculate V using following formula
V = + at
= 0
a = / m
a = 24N / 20 kg
a = 1.2m /
no place value in the formula of V
V = 0 + (1.2)(4)
V = 4.8 m/s
So,
Power = x V
Power = 24 x 4.8
Power = 115.2 W