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Maurinko [17]
3 years ago
11

A fill covering a wide area is to be placed at the surface of this profile. The fill has a total unit weight of 20 kN/m^3 and is

3 m thick. Assume that the data for the sample at 7.0 m are representative of the entire clay profile. Also assume that the clay is heavily over consolidated and that the danse sands at the surface of the profile are so stiff that they do not contribute to the settlement. Find the settlement of the surface due to compression of the clay layer
Engineering
1 answer:
goblinko [34]3 years ago
8 0

Answer:

hello your question lacks some information attached below is the complete question with the required information

answer : 81.63 mm

Explanation:

settlement of the surface due to compression of the clay ( new consolidated )

= 81.63 mm

attached below is a detailed solution to the given problem

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An engineer is designing a total hip implant. She intends to make the femoral stem out of titanium because it forms a good inter
makvit [3.9K]

Answer:

1. Yes.

2. Localized corrosion

Explanation:

Should she be worried about corrosion?

Yes, the engineer needs to be worried about corrosion as stainless steel has a lower resistance to corrosion, in other words, stainless steel corrodes faster than Titanium.

If so, what types of corrosion could take place?

The type of corrosion that takes place is called Localized corrosion. Localized corrosion occurs when a small part of a component experiences corrosion. In this case, the ball component of the femoral stem is made of stainless steel which will corrode faster than the other parts of the femoral stem which is made of Titanium.

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3 years ago
P9.28 A large vacuum tank, held at 60 kPa absolute, sucks sea- level standard air through a converging nozzle whose throat diame
eimsori [14]

Answer:

a)  m=0.17kg/s

b)  Ma=0.89

Explanation:

From the question we are told that:

Pressure P=60kPa

Diameter d=3cm

Generally at sea level

T_0=288k\\\\\rho_0=1.225kg/m^3\\\\P_0=101350Pa\\\\r=1.4

Generally the Power series equation for Mach number is mathematically given by

\frac{p_0}{p}=(1+\frac{r-1}{2}Ma^2)^{\frac{r}{r-1}}

\frac{101350}{60*10^3}=(1+\frac{1.4-1}{2}Ma^2)^{\frac{1.4}{1.4-1}}

Ma=0.89

Therefore

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\frac{\rho_0}{\rho}=(1+\frac{1.4-1}{2}(0.89)^2)^{\frac{1.4}{1.4-1}}

\frac{1.225}{\rho}=(1+\frac{1.4-1}{2}(0.89)^2)^{\frac{1.4}{1.4-1}}

\rho=0.848kg/m^3

Generally the equation for Velocity at throat is mathematically given by

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Where

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Therefore

V=0.89(1.4*288\sqrt{248})\\\\V=284

Generally the equation for Mass flow rate is mathematically given by

m=\rho*A*V

m=0.84*\frac{\pi}{4}*3*10^{-2}*284

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6 0
3 years ago
It is not a practical proposition to take direct measurements in nanoscale, but we can estimate variations in position and momen
Volgvan

Answer:

Answer is c Heisenberg's uncertainty principle

Explanation:

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Answer:

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