Question

Choose the correct vertex of the quadratic function f(x) = 3x2 - 2x - 1.

Answer 1

Answer:

vertex is $(\frac{-1}{3}, \frac{-4}{3})$

Step-by-step explanation:

f(x) = 3x^2 - 2x - 1

Given equation is in the form of f(x) = ax^2 + bx+c

a=3 , b=-2 , c=-1

To find x coordinate of vertex we use formula x= -b/2a

$x=\frac{-(-2)}{2(3)} = \frac{-1}{3}$

To find y coordinate of vertex plug in -1/3 in the place of x in f(X)

f(x) = 3x^2 - 2x - 1

$f(\frac{-1}{3})= 3(\frac{-1}{3})^2 -2(\frac{-1}{3})-1= \frac{-4}{3}$

So vertex is $(\frac{-1}{3}, \frac{-4}{3})$

Answer 2

The vertex is (1/3, -4/3)