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2 years ago

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Chemistry

1 answer:

NISA [10]2 years ago

3 0

Answer:

B: +3

Explanation:

If Gallium loses 3 electrons, it will become an ion.

The ion will be positively charged because in this new ion, the number of electrons is lesser than the number of protons. The charge difference will impart a positive net charge on the ion.

In a neutral atom, the number of electrons and protons are the same.
For positively charged ions, the number of protons is greater than the electrons

If Gallium the loss of 3 electrons offsets the charge balance in the chemical specie. Thus, the ion will have a net +3 charge.

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A typical adult human body contains approximately 2.500 L of blood plasma. How many grams of blood plasma are in the typical adu

kirill115 [55]

Answer:

$m=2.575g$

Explanation:

Hello,

In this case, since the density is defined as the ratio of the mass and volume:

$\rho =\frac{m}{V}$

We can compute the mass of blood as follows:

$m=\rho *V=1.03g/L*2.500L\\\\m=2.575g$

Best regards.

7 0

2 years ago

1 point

levacccp [35]

Answer:

A pure substance has a definite chemical composition

4 0

2 years ago

How would you prepare 500 mL of 0.360 M solution of CaCl2 from<br> solid CaCl2?

LenKa [72]

We need to measure 20.0 grams of CaCl₂ to prepare 500 mL of 0.360 M solution.

First, we need to determine the required moles of CaCl₂. We have 500 mL (0.500 L) of a 0.360 M solution (0.360 moles of CaCl₂ per liter of solution).

$0.500 L \times \frac{0.360mol}{L} = 0.180 mol$

Then, we will convert 0.180 moles to grams using the molar mass of CaCl₂ (110.98 g/mol).

$0.180 mol \times \frac{110.98g}{mol} = 20.0 g$

To prepare the solution, we weigh 20.0 g of CaCl₂ and add it to a beaker with enough distilled water to dissolve it. We stir it, heat it if necessary, and when we have a solution, we transfer it to a 500 mL flask and complete it to the mark with distilled water.

We need to measure 20.0 grams of CaCl₂ to prepare 500 mL of 0.360 M solution.

You can learn more about solutions here: brainly.com/question/2412491

4 0

1 year ago

I performed an experiment and mixed copper nitrate and potassium iodide. When they reacted, they formed a precipitate, even thou

Alexus [3.1K]

Answer:

2Cu2^+ + 2I^- ----> 2Cu^+ + I2

Explanation:

The reaction performed in the experiment is;

2 Cu(NO3)2 + 4 KI → 2 CuI (s) + 4 KNO3 + I2

The iodide ions reduces Cu^2+ to Cu^+ which is insoluble in water hence the precipitate. This is so because iodine is a good oxidizing agent seeing that it requires one electron to fill its outermost shell. Potassium on the other hand is a good reducing agent since it easily looses its one electron.

The oxidation - reduction equation is as follows;

2Cu2^+ + 2e ----> 2Cu^+ reduction half equation

2I^- ----> I2 + 2e. Oxidation half equation

Balanced redox reaction equation;

2Cu2^+ + 2I^- ----> 2Cu^+ + I2

3 0

2 years ago

Isotopes of the same element have different _____. numbers of neutrons numbers of protons numbers of electrons atomic numbers

iris [78.8K]

Answer:

number of neutrons

Explanation:

4 0

2 years ago

Read 2 more answers