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Radda [10]
3 years ago
6

Match the appropriate name for each chemical reaction description provided.

Chemistry
2 answers:
nasty-shy [4]3 years ago
4 0
Reaction 1 is a synthesis type of reactant because it involves combination of two elements. Reaction 2 is a decomposition type since it breaks down the original compound to more than 1 compounds or elements. Reaction 3 is a single replacement reaction. Reaction 4 is a combustion type since it uses oxygen. Reaction 4 is a neutralization double-displacement since it exchanges the places of cations at the same time it produces water. Reaction 5 is a precipitation double-replacement since it also <span>exchanges the places of cations at the same time produces a solid product.Answers are C, A, B, E, D, and F in order.</span>
kenny6666 [7]3 years ago
3 0

Answer:

1. Combination, since two reactant molecules are combined together to form a new addition molecule.

2. Decomposition, since one molecule gets converted into two compounds

3. Single replacement Reaction. Since Y is replaced by Z

4. Combustion reaction, reaction of hydrocarbons with excess Oxygen.

5. Neutralization, reaction of acid and base gives salt and water.

6. Double displacement reaction

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if 45.0 ml of 1.50 M Ca(OH)2 are needed to neutralize 25.0 ml of HI of unknown concentration, what is the molarity of the HI?
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M of HI = 5.4 M.

Explanation:

  • We have the rule: at neutralization, the no. of millimoles of acid is equal to the no. of millimoles of the base.

<em>(XMV) acid = (XMV) base.</em>

where, X is the no. of (H) or (OH) reproducible in acid or base, respectively.

M is the molarity of the acid or base.

V is the volume of the acid or base.

<em>(XMV) HI = (XMV) Ca(OH)₂.</em>

For HI; X = 1, M = ??? M, V = 25.0 mL.

For Ca(OH)₂, X = 2, M = 1.5 M, V = 45.0 mL.

<em>∴ M of HI = (XMV) Ca(OH)₂ / (XV) HI</em> = (2)(1.5 M)(45.0 mL) / (1)(25.0 mL) = <em>5.4 M.</em>

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