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Radda [10]
3 years ago
6

Match the appropriate name for each chemical reaction description provided.

Chemistry
2 answers:
nasty-shy [4]3 years ago
4 0
Reaction 1 is a synthesis type of reactant because it involves combination of two elements. Reaction 2 is a decomposition type since it breaks down the original compound to more than 1 compounds or elements. Reaction 3 is a single replacement reaction. Reaction 4 is a combustion type since it uses oxygen. Reaction 4 is a neutralization double-displacement since it exchanges the places of cations at the same time it produces water. Reaction 5 is a precipitation double-replacement since it also <span>exchanges the places of cations at the same time produces a solid product.Answers are C, A, B, E, D, and F in order.</span>
kenny6666 [7]3 years ago
3 0

Answer:

1. Combination, since two reactant molecules are combined together to form a new addition molecule.

2. Decomposition, since one molecule gets converted into two compounds

3. Single replacement Reaction. Since Y is replaced by Z

4. Combustion reaction, reaction of hydrocarbons with excess Oxygen.

5. Neutralization, reaction of acid and base gives salt and water.

6. Double displacement reaction

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Vera_Pavlovna [14]

The number of moles of gas present are 0.0054

<u>Explanation:</u>

Given-

Temperature, T = 100°C = 100 + 273 = 373K

Volume, V = 0.044L

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Moles of gas, n = ?

We know,

PV = nRT

R = 0.082 L.atm.K⁻¹.mol⁻¹

n = PV/RT

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7 0
3 years ago
If an object has a Mass of 11g and a volume fo 13mil, what is its density?
Nimfa-mama [501]

Answer:

\boxed {\boxed {\sf B. \ d \approx 0.85 \ g/mL}}

Explanation:

Density is found by dividing the mass by the volume.

d=\frac{m}{v}

The mass of the object is 11 grams and the volume is 13 milliliters.

m= 11 \ g \\v= 13 \ mL

Substitute the values into the formula.

d= \frac{11 \ g}{13 \ mL}

Divide.

d=0.846153846 \ g/mL

Round to the nearest hundredth. The 6 in the thousandth place tells us to round the 4 to a 5.

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