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Radda [10]
3 years ago
6

Match the appropriate name for each chemical reaction description provided.

Chemistry
2 answers:
nasty-shy [4]3 years ago
4 0
Reaction 1 is a synthesis type of reactant because it involves combination of two elements. Reaction 2 is a decomposition type since it breaks down the original compound to more than 1 compounds or elements. Reaction 3 is a single replacement reaction. Reaction 4 is a combustion type since it uses oxygen. Reaction 4 is a neutralization double-displacement since it exchanges the places of cations at the same time it produces water. Reaction 5 is a precipitation double-replacement since it also <span>exchanges the places of cations at the same time produces a solid product.Answers are C, A, B, E, D, and F in order.</span>
kenny6666 [7]3 years ago
3 0

Answer:

1. Combination, since two reactant molecules are combined together to form a new addition molecule.

2. Decomposition, since one molecule gets converted into two compounds

3. Single replacement Reaction. Since Y is replaced by Z

4. Combustion reaction, reaction of hydrocarbons with excess Oxygen.

5. Neutralization, reaction of acid and base gives salt and water.

6. Double displacement reaction

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Why might it be important to identify isoelectronic ions/atoms?
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Answer:

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Explanation:

5 0
2 years ago
The rate constant for the reaction is 0.660 M − 1 ⋅ s − 1 0.660 M−1⋅s−1 at 200 ∘ C. 200 ∘C. A ⟶ products A⟶products If the initi
Irina-Kira [14]

<u>Answer:</u> The concentration of A after 865 seconds is 0.00125 M

<u>Explanation:</u>

The integrated rate law equation for second order reaction follows:

k=\frac{1}{t}\left (\frac{1}{[A]}-\frac{1}{[A]_o}\right)

where,

k = rate constant = 0.660M^{-1}s^{-1}

t = time taken = 865 second

[A] = concentration of substance after time 't' = ?

[A]_o = Initial concentration = 0.00440 M

Putting values in above equation, we get:

0.660=\frac{1}{865}\left (\frac{1}{[A]}-\frac{1}{(0.00440)}\right)

[A]=0.00125M

Hence, the concentration of A after 865 seconds is 0.00125 M

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3 years ago
A 10g piece of metal absorbs 150 Joules of heat energy, and its temperature changes from 15° C to 130° C. Calculate the specific
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when you plug everything in you should get 0.1304J/g°C

I hope this helps. Let me know if anything is unclear.
7 0
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