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3 years ago

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A dolphin swims 665,280 feet in 3 hours. Use the formula dart, where d represents distance, r represents rate, and t represents

time, to answer the
following questions. Show your work.
Part A: Rearrange the distance formula, dart, to solve for rate. (2 points)
Part B: Find the dolphin's rate in feet per hour, (3 points)
Part C: Find the dolphin's rate in miles per hour. (3 points)
Part D: Which unit, feet, or miles, makes more sense to use in this scenario, and why? (2 points)

2 answers:

barxatty [35]3 years ago

5 0

Step-by-step explanation:

a) r=d/t ( same as formula of speed)

b) r= 665280/3=221760 feet/hr

c) distance in miles = 665280/5280= 126

so r=126/3 = 42 miles/hr

d) i think using miles makes more sense cz using feet will result in greater number of values so there is a greater chance of human error

____ [38]3 years ago

4 0

Adding answer so you can mark the original answer as brainliest!

Part A: r = d/t > 221,760 = 665,280/3

Part B: 221,750 feet/hour

Part C: 126 miles/hour (divide speed value by 5280

Part D: Miles makes more sense in this scenario because it is a larger unit of measurement and the dolphin travels a long distance.

<u>remember not to copy and paste! doing so will mark your answer as plagiarized if your teachers use a plagiarism detector </u>

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3 years ago

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MissTica

Answer:

Area: 135 ft^2

Perimeter: 50 ft

Step-by-step explanation:

area:

take the rectanle so length 12 x 9 = 108 so that is the length of the rectangle and now we need to find that of the triangle left over

subract 18 - 12 = 6 so that is the base of the trianle and we know the side length is 9 so plus it in A = (9)(6)/2

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the half-life of chromium-51 is 38 days. If the sample contained 510 grams. How much would remain after 1 year?

madam [21]

Answer:

About 0.6548 grams will be remaining.

Step-by-step explanation:

We can write an exponential function to model the situation. The standard exponential function is:

$f(t)=a(r)^t$

The original sample contained 510 grams. So, a = 510.

Each half-life, the amount decreases by half. So, r = 1/2.

For t, since one half-life occurs every 38 days, we can substitute t/38 for t, where t is the time in days.

Therefore, our function is:

$\displaystyle f(t)=510\Big(\frac{1}{2}\Big)^{t/38}$

One year has 365 days.

Therefore, the amount remaining after one year will be:

$\displaystyle f(365)=510\Big(\frac{1}{2}\Big)^{365/38}\approx0.6548$

About 0.6548 grams will be remaining.

Alternatively, we can use the standard exponential growth/decay function modeled by:

$f(t)=Ce^{kt}$

The starting sample is 510. So, C = 510.

After one half-life (38 days), the remaining amount will be 255. Therefore:

$255=510e^{38k}$

Solving for k:

$\displaystyle \frac{1}{2}=e^{38k}\Rightarrow k=\frac{1}{38}\ln\Big(\frac{1}{2}\Big)$

Thus, our function is:

$f(t)=510e^{t\ln(.5)/38}$

Then after one year or 365 days, the amount remaining will be about:

$f(365)=510e^{365\ln(.5)/38}\approx 0.6548$

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3 years ago

Jarvis works in a garage £6 an hour. If he works on Saturday, he is paid time and a quarter. If he works on Sunday, he is paid t

xxMikexx [17]

Answer: He is paid $90 last weekend.

Step-by-step explanation:

Since we have given that

Amount he earns per hour = $6

If he works on Saturday, he is paid time and a quarter .

Amount would be

$6\times 1.25=\$7.5$

If he works on Sunday, he is paid time and a half.

Amount would be

$6\times 1.5=\$9$

Number of hours he worked on Saturday = 6 hours

Number of hours he worked on Sunday = 5 hours

So, Total amount he is paid last weekend altogether is given by

$6\times 7.5+5\times 9\\\\=\$90$

Hence, he is paid $90 last weekend.

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3 years ago