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SOVA2 [1]
3 years ago
11

A 30-60-90 right triangle has a hypotenuse of 4 inches, What is the length in inches of the short leg? (The one opposite the 30

degree angle) Group of answer choices 2 √2 2 1/2 2 √3

Mathematics
1 answer:
Yuliya22 [10]3 years ago
7 0

Answer:

2

Step-by-step explanation:

In 30-60-90

The hypotenuse is always the short leg multiplied by 2

So going backward, 4/2 = 2

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Suppose xy=−4 and dy/dt=−3. Find dx/dt when x=−1.
user100 [1]
When x=-1: \quad (-1)y=-4\qquad\to\qquad y=4\)

Ok that gives us a little more information.
If we implicitly differentiate with respect to t, from the very start, then we can apply our product rule, ya?

x'y+xy'=0

The right side is zero, derivative of a constant is zero.
Where x' is dx/dt and y' is dy/dt.

From here, plug in all the stuff you know:
y' = -3
x = -1
y = 4

and solve for x'.

Hope that helps!
4 0
3 years ago
Multiplying desimals​
kolezko [41]

Answer:

Line up the numbers on the right - do not align the decimal points.

Starting on the right, multiply each digit in the top number by each digit in the bottom number, just as with whole numbers.

Add the products.

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Given: <br><br>EM, EQ-secants<br><br>Prove: MP·EW=WQ·EP
Dennis_Churaev [7]

Answer:

Step-by-step explanation:

A secant is a straight line from a point outside a given circle that passes through two points on its circumference.

From the given diagram, EM and EQ are secants.

Thus,

<PEW ≅ <WEP    (common angles)

<EMP ≅ <EQW (secant-chord theorem)

<WMP ≅ <PQM (inscribed angles of arc WP)

Therefore,

\frac{EW}{WM} = \frac{EP}{PQ}   (corresponding sides of a triangle)

This implies that,

EW*PQ = EP*WM

Therefore,

MP*EW = WQ*EP  (properties of a similar triangle)

7 0
3 years ago
Which graph represents a function?​
Pepsi [2]

Answer:

The answer to this is the last one, the on all the way at the bottom.

Step-by-step explanation:

This is because no 2 coordinates/points line up.

4 0
3 years ago
Simplify m(2+n-m)+3(3n+m^2-1)
mina [271]

Answer:2m^2+mn+2m+9n-3

Step-by-step explanation:

m(2+n-m)+3(3n+m^2-1)

open brackets

2m+mn-m^2+9n+3m^2-3

Collect like terms

3m^2-m^2+mn+2m+9n-3

2m^2+mn+2m+9n-3

4 0
3 years ago
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